折半查找.bak

常用算法

clear
dime a(10)
n=10
for i=1 to 10
   a(i)=int(rand()*100)
   ??a(i)
 next 
*排序 
 for i=1 to n-1
    for j=n to i+1 step -1
      if a(j)<a(j-1)
       t=a(j)
       a(j)=a(j-1)
       a(j-1)=t
       endif
   next j
   next i
   ?"sort:"
   for i=1 to n
    ?? a(i)
   next i
  *折半查找
  input "输入要查找的数："to x
  l=1
  h=10
  do while l<=h
    m=int((l+h)/2)
    if a(m)=x then 
     exit 
    else
      if a(m)>x then
         h=m-1
      else 
         l=m+1
       endif
    endif
    enddo
    if l<=h then 
    ?"找到",M,a(m)
    else
     ?"没有找到！"
     endif