冒泡法排序.bak
来自「常用算法」· BAK 代码 · 共 21 行
BAK
21 行
clear
dime a(10)
n=10
for i=1 to 10
a(i)=int(rand()*100)
??a(i)
next
for i=1 to n-1
for j=n to i+1 step -1
if a(j)>a(j-1)
t=a(j)
a(j)=a(j-1)
a(j-1)=t
endif
next j
next i
?"sort:"
for i=1 to n
?? a(i)
next i
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