fnmatch.py
来自「mallet是自然语言处理、机器学习领域的一个开源项目。」· Python 代码 · 共 108 行
PY
108 行
"""Filename matching with shell patterns.fnmatch(FILENAME, PATTERN) matches according to the local convention.fnmatchcase(FILENAME, PATTERN) always takes case in account.The functions operate by translating the pattern into a regularexpression. They cache the compiled regular expressions for speed.The function translate(PATTERN) returns a regular expressioncorresponding to PATTERN. (It does not compile it.)"""import re__all__ = ["fnmatch","fnmatchcase","translate"]_cache = {}def fnmatch(name, pat): """Test whether FILENAME matches PATTERN. Patterns are Unix shell style: * matches everything ? matches any single character [seq] matches any character in seq [!seq] matches any char not in seq An initial period in FILENAME is not special. Both FILENAME and PATTERN are first case-normalized if the operating system requires it. If you don't want this, use fnmatchcase(FILENAME, PATTERN). """ import os name = os.path.normcase(name) pat = os.path.normcase(pat) return fnmatchcase(name, pat)def filter(names, pat): """Return the subset of the list NAMES that match PAT""" import os,posixpath result=[] pat=os.path.normcase(pat) if not _cache.has_key(pat): res = translate(pat) _cache[pat] = re.compile(res) match=_cache[pat].match if os.path is posixpath: # normcase on posix is NOP. Optimize it away from the loop. for name in names: if match(name): result.append(name) else: for name in names: if match(os.path.normcase(name)): result.append(name) return resultdef fnmatchcase(name, pat): """Test whether FILENAME matches PATTERN, including case. This is a version of fnmatch() which doesn't case-normalize its arguments. """ if not _cache.has_key(pat): res = translate(pat) _cache[pat] = re.compile(res) return _cache[pat].match(name) is not Nonedef translate(pat): """Translate a shell PATTERN to a regular expression. There is no way to quote meta-characters. """ i, n = 0, len(pat) res = '' while i < n: c = pat[i] i = i+1 if c == '*': res = res + '.*' elif c == '?': res = res + '.' elif c == '[': j = i if j < n and pat[j] == '!': j = j+1 if j < n and pat[j] == ']': j = j+1 while j < n and pat[j] != ']': j = j+1 if j >= n: res = res + '\\[' else: stuff = pat[i:j].replace('\\','\\\\') i = j+1 if stuff[0] == '!': stuff = '^' + stuff[1:] elif stuff[0] == '^': stuff = '\\' + stuff res = '%s[%s]' % (res, stuff) else: res = res + re.escape(c) return res + "$"
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