📄 pr0720.cpp
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// Programming with C++, Second Edition, by John R. Hubbard
// Copyright McGraw-Hill, 2000
// Problem 7.20 on page 176
// Integrating a function
#include <cmath> // defines the sqrt() function
#include <iostream> // defines the cout object
using namespace std;
const double E=2.718281828459045;
const double P=3.141592653589793;
const double P2=P/2;
double riemann(double(*)(double),double,double,int);
int main()
{ cout << "riemann(sqrt,1,4,100) = " << riemann(sqrt,1,4,100) << endl;
cout << "riemann(sqrt,1,4,1000) = " << riemann(sqrt,1,4,1000) << endl;
cout << "riemann(sqrt,1,4,10000) = " << riemann(sqrt,1,4,10000) << endl;
cout << "The exact integral = " << 14.0/3 << endl;
cout << "riemann(cos,0,P2,100) = " << riemann(cos,0,P2,100) << endl;
cout << "riemann(cos,0,P2,1000) = " << riemann(cos,0,P2,1000) << endl;
cout << "riemann(cos,0,P2,10000) = " << riemann(cos,0,P2,10000) << endl;
cout << "The exact integral = " << 1 << endl;
cout << "riemann(exp,0,1,100) = " << riemann(exp,0,1,100) << endl;
cout << "riemann(exp,0,1,1000) = " << riemann(exp,0,1,1000) << endl;
cout << "riemann(exp,0,1,10000) = " << riemann(exp,0,1,10000) << endl;
cout << "The exact integral = " << E - 1 << endl;
cout << "riemann(log,1,E,100) = " << riemann(log,1,E,100) << endl;
cout << "riemann(log,1,E,1000) = " << riemann(log,1,E,1000) << endl;
cout << "riemann(log,1,E,10000) = " << riemann(log,1,E,10000) << endl;
cout << "The exact integral = " << 1 << endl;
}
double riemann(double (*pf)(double t), double a, double b, int n)
{ // returns the left Riemann sum [f(a)*h + f(a+h)*h + . . . + f(b-h)*h],
// for the integral of f over [a,b], where f() = *pf() and h = (b-a)/n:
double s = 0, h = (b-a)/n, x;
int i;
for (x = a, i = 0; i < n; x += h, i++)
s += (*pf)(x);
return s*h;
}
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