117.c
来自「平时acm训练时ac的源代码」· C语言 代码 · 共 64 行
C
64 行
/*
117. Counting
Accepted 98 ms 114 kb
*/
#include <stdio.h>
int main()
{
int N, M, K, i, t, j, y, tc;
int count=0, zysc=0;
int zys[26][2];
scanf("%d %d %d", &N, &M, &K);
if (0==K%2)
{
zysc = 1;
zys[0][0] = 2;
zys[0][1] = 1;
K=K/2;
for (; 0==K%2;)
{
K=K/2;
zys[0][1]++;
}
}
for (i=3; 1!=K; i++)
{
if (0==K%i)
{
zys[zysc][0] = i;
zys[zysc][1] = 1;
K=K/i;
for (; 0==K%i; )
{
K=K/i;
zys[zysc][1]++;
}
zysc = zysc+1;
}
}
for (i=0; i<N; i++)
{
scanf("%d", &t);
for (y=1, j=0; j<zysc; j++)
{
for (tc=0; 0==t%zys[j][0]; )
{
t = t/zys[j][0];
tc++;
}
if (tc*M<zys[j][1])
{
y=0;
break;
}
}
if (1==y)
{
count = count+1;
}
}
printf("%d", count);
}
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