1135.pas

来自「平时acm训练时ac的源代码」· PAS 代码 · 共 18 行

var i,n,L,R:longint;
    ch:char;
begin
 readln(n);
 L:=0;
 R:=0;
 for i:=1 to n do
 begin
  read(ch);
  while not(ch in ['<','>']) do
   read(ch);
  case ch of
   '>':inc(R);
   '<':inc(L,R);
  end;
 end;
 writeln(L);
end.