1032.pas
来自「平时acm训练时ac的源代码」· PAS 代码 · 共 17 行
PAS
17 行
program cgp;
var n,i,j,t:integer;
a,s:array[0..10000]of 0..15000;
begin
read(n);fillchar(a,sizeof(a),0);fillchar(s,sizeof(s),0);
for i:=1 to n do begin
read(a[i]);
s[i]:=(a[i]+s[i-1])mod n;
if s[i]=0 then begin writeln(i);for j:=1 to i do writeln(a
[j]);halt;end;
end;
for i:=1 to n-1 do
for j:=i+1 to n do
if s[i]=s[j] then begin
writeln(j-i);
for t:=i+1 to j do writeln(a[t]);halt;end;
end.
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