1100.pas

来自「平时acm训练时ac的源代码」· PAS 代码 · 共 17 行

PAS
17
字号
program a1100;
const nn=150001;
type rec=record
     id:longint;
     m:byte;
     end;
var a:array[1..nn] of rec;
   j,i,n:longint;

begin
readln(n);
for i:=1 to n do
   readln(a[i].id,a[i].m);
for j:=100 downto 0 do
   for i:=1 to n do
      if a[i].m=j then writeln(a[i].id,' ',a[i].m);
end.

⌨️ 快捷键说明

复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?