fsqfindpn.m

来自「该代码为排队论工具.用于MM1,MG1等模型.」· M 代码 · 共 29 行

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29
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%fsqfindpn(lambda,mu,c,m,n)
%   This function finds the probability there are n machines down
%   (in the system) for a machine repair problem (finite source queue).

function out = fsqfindpn(lambda,mu,c,m,n)

p0 = fsqfindp0(lambda,mu,c,m);

if n == 0
    pn = p0;
end

if n >= 1
    if n < c
        pn = nchoosek(m,n)*(lambda/mu)^n*p0;
    end
end

if n >= c
    if n <= m
        pn = nchoosek(m,n)*(lambda/mu)^n*p0*factorial(n)/(factorial(c)*c^(n-c));
    end
end

if n > m
    pn = 0;
end

out = pn;

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