共阴多机主机串行校验和.c

单片机C语言15个实验附有原理图和程序 是我的课程作业 以经过实践验证

//computer11.c
#include <stdio.h>
#include <reg51.h>
#include <intrins.h>
unsigned  char code ledk[17]={0x3f,0x06,0x5b,0x4f,0x66,0x6D,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71,0x00};
unsigned char key,buf[15],flag,a[10]={9,8,7,6,5,4,3,2,1,0};b[6]={10,11,12,13,14,15};
sbit P37=P3^7;sbit clk=P0^7;sbit sda=P0^6;               //74LS164
void delay(unsigned int n)
{unsigned int i;
 for(i=0;i<n;i++);}
/*void hextodec()
 {unsigned int xx;
  disp[3]=disp_value/1000; xx=disp_value%1000;
  disp[2]=xx/100;          xx=xx%100;
  disp[1]=xx/10;           
  disp[0]=xx%10;   }*/
void shift(unsigned char dx)
{static unsigned char d;
   unsigned char j=0;
    d=dx;
   	while(j<8)
	{if((d&0x80)!=0) sda=1;
       else  sda=0;
	   clk=0;clk=1;
	   d<<=1;j++;}  }
//================
unsigned char get_char(void)
{unsigned char	key_code;
  if (P37!=0 )key_code=0xff;else if (P37==0)key_code=0;
  return(key_code);}
void key_func(key)
{switch(key){case  0: flag=1;break;
             default: break;}}
void send()
{unsigned char i,no=8,sum=0;
 buf[0]=no;
 for(i=0;i<=no;i++){buf[i+1]=a[i];sum=sum+a[i];}
 buf[no+2]=sum;
 for(i=0;i<=no+2;i++){SBUF=buf[i];while(!TI);TI=0;}}

void send1()
{unsigned char i,no=5,sum=0;
 buf[0]=no;
 for(i=0;i<=no;i++){buf[i+1]=b[i];sum=sum+b[i];}
 buf[no+2]=sum;
 for(i=0;i<=no+2;i++){SBUF=buf[i];while(!TI);TI=0;}}

void main(void)
{flag=0;TMOD=0x20;TH1=0xf3;TL1=0xf3;TR1=1;
 SCON=0xd0;PCON=0x00;P2=0xee;//TH1=0xcc;TL1=0xcc;
  while(1)
     {P2=0xee;
      key=get_char( );
      key_func(key);
	  if(flag==1){do{TB8=1;
                     SBUF=0x01;while(!TI);TI=0;
				     do{}while(!RI);RI=0;}while(SBUF!=0x01);
                  TB8=0;
                  send();
				  shift(ledk[SBUF]|0x80);delay(50000);shift(0);
			      
				  delay(65000);delay(65000);delay(65000);
                  
				  do{TB8=1;
                     SBUF=0x02;while(!TI);TI=0;
				     do{}while(!RI);RI=0;}while(SBUF!=0x02);
                  TB8=0;
                  send1();
				  shift(ledk[SBUF]|0x80);delay(50000);shift(0);

			      delay(65000);delay(65000);delay(65000);
				  delay(65000);delay(65000);delay(65000);
                  delay(65000);delay(65000);delay(65000);
				  delay(65000);delay(65000);delay(65000); }                                          
      else {shift(0);}
	}		   
 }