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lang=EN-US>(a[i]</SPAN><SPAN style="FONT-FAMILY: 宋体">，…，</SPAN><SPAN
lang=EN-US>a[Count-1))</SPAN><SPAN
style="FONT-FAMILY: 宋体">两个部分组成；初始时</SPAN><SPAN
lang=EN-US>i</SPAN><SPAN style="FONT-FAMILY: 宋体">等于</SPAN><SPAN
lang=EN-US>1</SPAN><SPAN
style="FONT-FAMILY: 宋体">，每趟排序时将无序部分中的第一个元素</SPAN><SPAN
lang=EN-US>a[i]</SPAN><SPAN
style="FONT-FAMILY: 宋体">插入到有序部分中的恰当位置，共需进行</SPAN><SPAN
lang=EN-US>count-1</SPAN></FONT><SPAN style="FONT-FAMILY: 宋体"><FONT
size=2>趟，最终使整个数组有序。</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>[</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">函数</SPAN></FONT><SPAN lang=EN-US><FONT
size=2>3.1]</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>void insert_sort(int a[] , int
count)</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>{ int i, j, t;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> for(i=1 ; i<count ;
i++) </FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><SPAN
lang=EN-US><FONT size=2>{ /*</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">控制</SPAN><SPAN lang=EN-US>a[i],</SPAN><SPAN
style="FONT-FAMILY: 宋体">……</SPAN><SPAN lang=EN-US>,
a[count-1]</SPAN><SPAN
style="FONT-FAMILY: 宋体">的比较和插入</SPAN></FONT><SPAN lang=EN-US><FONT
size=2>*/</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><SPAN
lang=EN-US><FONT size=2> t=a[i];</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><SPAN
lang=EN-US><FONT size=2> j=<U> (1)
</U>;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><SPAN
lang=EN-US><FONT size=2> while (j>=0 &&
t<a[j])</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><SPAN
lang=EN-US><FONT size=2> { /*</FONT></SPAN><FONT
size=2><SPAN style="FONT-FAMILY: 宋体">在有序部分中寻找元素</SPAN><SPAN
lang=EN-US>a[i]</SPAN><SPAN
style="FONT-FAMILY: 宋体">的插入位置</SPAN></FONT><SPAN lang=EN-US><FONT
size=2>*/</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><SPAN
lang=EN-US><FONT size=2>
<U> (2) </U>;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><I><SPAN
lang=EN-US><FONT size=2>
</FONT></SPAN></I><SPAN lang=EN-US><FONT
size=2> j--;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><SPAN
lang=EN-US><FONT size=2> }</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><SPAN
lang=EN-US><FONT size=2> <U> (3)
</U>;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 42.75pt"><SPAN
lang=EN-US><FONT size=2>}</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 17.95pt"><SPAN
lang=EN-US><FONT size=2>}</FONT></SPAN></P>
<P class=MsoNormal><SPAN lang=EN-US><FONT
size=2>[</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">函数</SPAN><SPAN lang=EN-US>3</SPAN><SPAN
style="FONT-FAMILY: 宋体">．</SPAN><SPAN lang=EN-US>2</SPAN><SPAN
style="FONT-FAMILY: 宋体">说明</SPAN></FONT><SPAN lang=EN-US><FONT
size=2>]</FONT></SPAN></P>
<P class=MsoNormal><SPAN lang=EN-US><FONT size=2>
</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">递归函数</SPAN><SPAN lang=EN-US>invert(int
a[]</SPAN><SPAN style="FONT-FAMILY: 宋体">，</SPAN><SPAN lang=EN-US>int
k)</SPAN><SPAN style="FONT-FAMILY: 宋体">将指定数组中的前</SPAN><SPAN
lang=EN-US>k</SPAN></FONT><SPAN style="FONT-FAMILY: 宋体"><FONT
size=2>个元素逆置。</FONT></SPAN></P>
<P class=MsoNormal><SPAN lang=EN-US><FONT
size=2>[</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">函数</SPAN><SPAN lang=EN-US>3</SPAN><SPAN
style="FONT-FAMILY: 宋体">．</SPAN></FONT><SPAN lang=EN-US><FONT
size=2>2]</FONT></SPAN></P>
<P class=MsoNormal><SPAN lang=EN-US><FONT size=2>void invert(int a[]
, int k);</FONT></SPAN></P>
<P class=MsoNormal><SPAN lang=EN-US><FONT size=2>{ int
t;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>if (<U> (4) </U>)
{</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> invert(<U> (5)
</U>);</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> t=a[0];</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> a[0]=a[k-1];</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> a[k-1]=t;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>}</FONT></SPAN></P>
<P class=MsoNormal><SPAN lang=EN-US><FONT size=2>}</FONT></SPAN></P>
<P class=MsoNormal><SPAN style="FONT-FAMILY: 宋体"><FONT
size=2>试题四</FONT></SPAN></P>
<P class=MsoNormal><SPAN lang=EN-US><FONT size=2>
</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">阅读下列程序说明和</SPAN><SPAN
lang=EN-US>C</SPAN><SPAN
style="FONT-FAMILY: 宋体">代码，将应填入</SPAN><U><SPAN lang=EN-US>
(n) </SPAN></U></FONT><SPAN style="FONT-FAMILY: 宋体"><FONT
size=2>处的字句写在答题纸的对应栏内。</FONT></SPAN></P>
<P class=MsoNormal><SPAN lang=EN-US><FONT
size=2>[</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">程序</SPAN><SPAN lang=EN-US>4</SPAN><SPAN
style="FONT-FAMILY: 宋体">说明</SPAN></FONT><SPAN lang=EN-US><FONT
size=2>]</FONT></SPAN></P>
<P class=MsoNormal><SPAN lang=EN-US><FONT size=2>
</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">本程序用古典的</SPAN><SPAN
lang=EN-US>Eratosthenes</SPAN><SPAN
style="FONT-FAMILY: 宋体">的筛法求从</SPAN><SPAN lang=EN-US>2</SPAN><SPAN
style="FONT-FAMILY: 宋体">起到指定范围内的素数。如果要找出</SPAN><SPAN
lang=EN-US>2</SPAN><SPAN style="FONT-FAMILY: 宋体">至</SPAN><SPAN
lang=EN-US>10</SPAN><SPAN
style="FONT-FAMILY: 宋体">中的素数，开始时筛中有</SPAN><SPAN
lang=EN-US>2</SPAN><SPAN style="FONT-FAMILY: 宋体">到</SPAN><SPAN
lang=EN-US>10</SPAN><SPAN
style="FONT-FAMILY: 宋体">的数，然后取走筛中的最小的数</SPAN><SPAN
lang=EN-US>2</SPAN><SPAN
style="FONT-FAMILY: 宋体">，宣布它是素数，并把该素数的倍数都取走。这样，第一步以后，筛子中还留下奇数</SPAN><SPAN
lang=EN-US>3</SPAN><SPAN style="FONT-FAMILY: 宋体">、</SPAN><SPAN
lang=EN-US>5</SPAN><SPAN style="FONT-FAMILY: 宋体">、</SPAN><SPAN
lang=EN-US>7</SPAN><SPAN style="FONT-FAMILY: 宋体">、</SPAN><SPAN
lang=EN-US>9</SPAN><SPAN
style="FONT-FAMILY: 宋体">：重复上述步骤，再取走最小数</SPAN><SPAN
lang=EN-US>3</SPAN><SPAN
style="FONT-FAMILY: 宋体">，宣布它为素数，并取走</SPAN><SPAN
lang=EN-US>3</SPAN><SPAN
style="FONT-FAMILY: 宋体">的倍数，于是留下</SPAN><SPAN
lang=EN-US>5</SPAN><SPAN style="FONT-FAMILY: 宋体">、</SPAN><SPAN
lang=EN-US>7</SPAN><SPAN
style="FONT-FAMILY: 宋体">。反复重复上述步骤，直至筛中为空时，工作结束，求得</SPAN><SPAN
lang=EN-US>2</SPAN><SPAN style="FONT-FAMILY: 宋体">至</SPAN><SPAN
lang=EN-US>10</SPAN></FONT><SPAN style="FONT-FAMILY: 宋体"><FONT
size=2>中的全部素数。</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
style="FONT-FAMILY: 宋体"><FONT size=2>程序中用数组</FONT></SPAN><FONT
size=2><SPAN lang=EN-US>sieve</SPAN><SPAN
style="FONT-FAMILY: 宋体">表示筛子，数组元素</SPAN><SPAN
lang=EN-US>sieve[i]</SPAN><SPAN
style="FONT-FAMILY: 宋体">的值为</SPAN><SPAN lang=EN-US>1</SPAN><SPAN
style="FONT-FAMILY: 宋体">时，表示数</SPAN><SPAN lang=EN-US>i</SPAN><SPAN
style="FONT-FAMILY: 宋体">在筛子中，值为</SPAN><SPAN
lang=EN-US>-1</SPAN><SPAN style="FONT-FAMILY: 宋体">时表示数</SPAN><SPAN
lang=EN-US>i</SPAN></FONT><SPAN style="FONT-FAMILY: 宋体"><FONT
size=2>已被取走。</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>[</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">程序</SPAN></FONT><SPAN lang=EN-US><FONT
size=2>4]</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>#include <stdio.h></FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>#define MAX 22500</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>main()</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>{ unsigned int i , range , factor , k
;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> int sieve[MAX]
;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> printf(“please input the range
: ”);</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> scanf(“%d”,&range);
/*range</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">指出在多大的范围内寻找素数</SPAN></FONT><SPAN
lang=EN-US><FONT size=2> */</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> for (i=2 ; i<=range ;
i++) /* </FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">筛子初始化</SPAN></FONT><SPAN lang=EN-US><FONT
size=2> */</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>
<U> (1) </U>;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> factor=2 ;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> while (factor<=range)
{</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2> if (<U>
(2) </U>) { /*</FONT></SPAN><FONT
size=2><SPAN style="FONT-FAMILY: 宋体">筛子最小数是素数</SPAN></FONT><SPAN
lang=EN-US><FONT size=2> */</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>
printf(“%d\t”,factor);</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>
k=factor;</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 21.75pt"><SPAN
lang=EN-US><FONT size=2>
while (k<=range) </FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 63.75pt"><SPAN
lang=EN-US><FONT size=2>{ /*</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">移走素数的倍数</SPAN></FONT><SPAN lang=EN-US><FONT
size=2> */</FONT></SPAN></P>
<P class=MsoNormal style="TEXT-INDENT: 63.75pt"><SPAN
lang=EN-US><FONT size=2> <U> (3)
</U>; /*</FONT></SPAN><FONT size=2><SPAN
style="FONT-FAMILY: 宋体">筛中的个数减一</SPAN></FONT><SPAN lang=EN-US><FONT
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