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📄 form1.frm

📁 用VB读取dxf中数据.如果你不是专业开发CAD系统软件的
💻 FRM
字号:
VERSION 5.00
Begin VB.Form Form1 
   Caption         =   "Form1"
   ClientHeight    =   2496
   ClientLeft      =   48
   ClientTop       =   336
   ClientWidth     =   3744
   LinkTopic       =   "Form1"
   ScaleHeight     =   2496
   ScaleWidth      =   3744
   StartUpPosition =   3  '窗口缺省
   Begin VB.TextBox Text1 
      Height          =   612
      Left            =   720
      TabIndex        =   1
      Text            =   "Text1"
      Top             =   360
      Width           =   1812
   End
   Begin VB.CommandButton Command1 
      Caption         =   "Command1"
      Height          =   612
      Left            =   1560
      TabIndex        =   0
      Top             =   1200
      Width           =   1572
   End
End
Attribute VB_Name = "Form1"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = False
Attribute VB_PredeclaredId = True
Attribute VB_Exposed = False
Private Sub Command1_Click()
'cmndia.ShowOpen
Text1.Text = "芜湖地形.dxf"
Dim fn As String
Dim strType As String, strCon1 As String, strCon2 As String, strCon3 As String
Dim strCon As String
Dim x, y, z As Double
Open "out.txt" For Output As #2
Dim b1 As Boolean
fn = "芜湖地形.dxf"
Open fn For Input As #1
While Not EOF(1)
Input #1, strType
If strType = "POINT" Then
    Input #1, strCon1
    If strCon1 = "10" Then
       Input #1, x
    Else
       GoTo nextone
    End If
    Input #1, strCon2
    If strCon2 = "20" Then
      Input #1, y
    Else
      GoTo nextone
    End If
    Input #1, strCon3
    If strCon3 = "30" Then
      Input #1, z
    Else
      GoTo nextone
    End If
     Write #2, x; y; z
    'b1 = False
    'Do
     ' Input #1, strCon
     ' If strCon = "1" Then
     '    z = 0                    'if input 汉字,则z为0。
       'but such as "1桥",则z为1。
     '    Input #1, z
     '    If Abs(z) > 0 Then
      '      Write #2, x; y; z
     '       Debug.Print x; y; z
     '       b1 = True
      '   End If
    '  End If
  '  Loop Until b1
    
End If
nextone:
Wend

Close 1
Close 2

End Sub


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