📄 pretbtree.h
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//#include"TBTree.h"
#include<iostream.h>
#include<strstrea.h>
#include<string.h>
#include<stdlib.h>
#include<iomanip.h>
struct TreeNode1{
char data;
int ltag;
int rtag;
TreeNode1*left;
TreeNode1*right;
};
class PreTree
{
public:
TreeNode1 *BT;
TreeNode1 *pre;
PreTree();
void CreatPreTree();
void Print(TreeNode1*p);
void ThreadPreTree(TreeNode1*p);
void PrintPreTBTree(TreeNode1*p);
TreeNode1* PreTBTreePre(TreeNode1*p);
TreeNode1* PreTBTreeNext(TreeNode1*p);
void Print1(TreeNode1*p);
};
PreTree::PreTree(){
BT=NULL;
pre=NULL;
}
void PreTree::CreatPreTree()
{
TreeNode1* s[10];
int top=-1;
TreeNode1*p;
int k;
char a[50];
b:
int i=0;
cout<<"输入以'@'字符为结束符的二叉树广义表表示:"<<endl;
char shu;
cin>>shu;
while(shu!='@'){
a[i++]=shu;
cin>>shu;
}
if(a[0]=='('||a[0]==')'||a[0]==','||a[i-1]!=')'){
cout<<"广义表输入有错!请重新输入......"<<endl<<endl;
goto b;
}
for(int j=0;j<i-1;j++){
if(a[j]==','&&a[j+1]==','){
cout<<"广义表输入有错!请重新输入......"<<endl<<endl;
goto b;}
if(a[j]=='('&&a[j+1]=='('){
cout<<"广义表输入有错!请重新输入......"<<endl<<endl;
goto b;
}
if((a[j]!='('&&a[j]!=','&&a[j]!=')')&&(a[j+1]!='('&&a[j+1]!=','&&a[j+1]!=')')){
cout<<"广义表输入有错!请重新输入......"<<endl<<endl;
goto b;
}
}
a[i++]='@';
istrstream ins(a);
char ch;
ins>>ch;
while(ch!='@')
{
switch(ch)
{
case'(':
top++;s[top]=p;k=1;
break;
case')':
top--;
break;
case',':
k=2;
break;
default:
p=new TreeNode1;
p->ltag=0;
p->rtag=0;
p->data=ch;
p->left=p->right=NULL;
if(BT==NULL)BT=p;
else
{
switch(k)
{
case 1:
s[top]->left=p;
break;
case 2:
s[top]->right=p;
}
}
}
ins>>ch;
}
}
void PreTree::Print(TreeNode1*p){
if(p!=NULL){
cout<<p->data;
if(p->left!=NULL||p->right!=NULL){
cout<<'(';
Print(p->left);
if(p->right!=NULL)cout<<',';
Print(p->right);
cout<<')';
}
}
}
void PreTree::ThreadPreTree(TreeNode1*p){
if(p!=NULL){
if(pre!=NULL&&pre->rtag==1)pre->right=p;
if(p->left==NULL){
p->ltag=1;
p->left=pre;
}
if(p->right==NULL){
p->rtag=1;
}
pre=p;
if(p->ltag==0)ThreadPreTree(p->left);
if(p->rtag==0)ThreadPreTree(p->right);
}
}
void PreTree::PrintPreTBTree(TreeNode1*p)
{
while(p!=NULL){
cout<<p->data<<setw(5);
p=PreTBTreeNext(p);
}
}
TreeNode1*PreTree::PreTBTreeNext(TreeNode1*p){
if(p->ltag==1)return p->right;
else return p->left;
}
TreeNode1*PreTree::PreTBTreePre(TreeNode1*p){
if(p->ltag==1)return p->left;
else return NULL;
}
void PreTree::Print1(TreeNode1*p){
TreeNode1*pq;
while(p!=NULL){
cout<<setw(8)<<p->data<<setw(8)<<p->ltag<<setw(8);
if(p->ltag==1)
{
pq=PreTBTreePre(p);
if(pq!=NULL)cout<<pq->data<<setw(8);
else cout<<"NULL"<<setw(8);
}
else cout<<setw(16);
cout<<p->rtag<<setw(8);
if(p->rtag==1)
{
pq=PreTBTreeNext(p);
if(pq!=NULL)cout<<pq->data<<setw(8);
else cout<<"NULL"<<setw(8);
}
else cout<<setw(8);
p=PreTBTreeNext(p);
cout<<endl;
}
}
void choice1(){
system("cls");
cout<<endl;
cout<<" --------------前序线索二叉树的前序遍历--------------"<<endl<<endl;
char c1;
do{
PreTree HT=PreTree();
HT.CreatPreTree();
cout<<endl;
cout<<"二叉树初始状态广义表形式的输出:";
HT.Print(HT.BT);
cout<<endl<<endl;
HT.ThreadPreTree(HT.BT);
cout<<"对建立的二叉线索树进行前序遍历,序列为:";
HT.PrintPreTBTree(HT.BT);
cout<<endl<<endl;
cout<<"按前序遍历序列显示各结点的线索以及所指结点:"<<endl<<endl;
cout<<setw(42)<<"结点 左线索 左指针 右线索 右指针"<<endl<<endl;
HT.Print1(HT.BT);
cout<<endl;
cout<<"是否继续(y/n)";
cin>>c1;
}while(c1=='y'||c1=='Y');
}
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