roletypeaction.java

使用spring ,hibernate 框架的稽查管理系统

package com.je.ims.controller.c852;

import java.util.HashMap;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;
import java.util.StringTokenizer;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;

import org.springframework.web.bind.RequestUtils;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.Controller;

import com.chttl.im.organization.Person;
import com.je.ims.dao.C852RoleTypeDAO;
import com.je.ims.hibernate.RoleType;
import com.je.ims.util.MenuUtils;
public class RoleTypeAction implements Controller {

	private C852RoleTypeDAO dao;
	private int right=-1;
	public void setDao(C852RoleTypeDAO dao)
	{
		this.dao=dao;
	}
		public ModelAndView handleRequest(HttpServletRequest arg0,
				HttpServletResponse arg1) throws Exception {
			HttpSession session=arg0.getSession();
			LinkedList list=(LinkedList)session.getAttribute("menu");
			right=MenuUtils.getMenuRight(list,"roleType.do");
			session.setAttribute("/view/c852.jsp",new Integer(right));
			ModelAndView model=null;
			String method=null;
			try{
				method=new String(RequestUtils.getRequiredStringParameter(arg0, "method").getBytes("ISO-8859-1"),"MS950");
			}
			catch(Exception e){
				if(right==1||right==0)
				model=handleRoleType(arg0,arg1);
				else
				{
					String errormessage="眤礚