check.c

来自「harvest是一个下载html网页得机器人」· C语言 代码 · 共 73 行

C
73
字号
/*** Copyright (C) 1995, Enterprise Integration Technologies Corp.        ** All Rights Reserved.** Kevin Hughes, kevinh@eit.com ** 3/11/94**** This file was released under the GPL by EIT in October 1997**** Heavily modified for Harvest by Simon Wilkinson (sxw@tardis.ed.ac.uk)*/#include "swish.h"#include "check.h"#include "hash.h"/* Should a word be indexed? Consults the stopword hash list** and checks if the word is of a reasonable length...** If you have any good rules that can work with most languages,** please let me know...*/int isokword(char *word){        int i, same, hasnumber, hasvowel, hascons,		numberrow, vowelrow, consrow;	char lastchar;	if (word[0] == '\0') return 0;        if (isstopword(word)) return 0;        if (strlen(word) < MINWORDLIMIT || strlen(word) > MAXWORDLIMIT)                return 0;	return 1;}/* Does a word have valid characters?*/int hasokchars(char *word){	int i, j;	char c;	c = word[strlen(word) - 1];	for (i = j = 0; BEGINCHARS[i] != '\0'; i++)		if (word[0] == BEGINCHARS[i])			j++;	if (!j)		return 0;	for (i = j = 0; ENDCHARS[i] != '\0'; i++)		if (c == ENDCHARS[i])			j++;	if (!j)		return 0;	for (i = 0; word[i] != '\0'; i++)		for (j = 0; WORDCHARS[j] != '\0'; j++)			if (word[i] == WORDCHARS[j])				return 1;	return 0;}/* Is a letter a vowel?*/int isvowel(char c){	if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')		return 1;	return 0;}

⌨️ 快捷键说明

复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?