rayleigh_duojing.m

考虑了瑞利衰落信道下的情况,设置了5,10,20条多径,有完美的仿真结果

% 编一个如瑞利多径的信道函数；
function y=Rayleigh_DuoJing(x,sigma,num_path,ray_factor,time_delay,p_path)

y=zeros(num_path,size(x,2));
for i=1:num_path
    % 即使瑞利衰落因子是一样的，
    % 对于每一行的衰落系数也要分别产生；
    ray_number=raylrnd(ray_factor,size(x));
    y(i,:)=sqrt(10^(p_path(i)/10))*(ray_number.*x);
    temp=y(i,:);
    y(i,:)=[zeros(1,time_delay(i)),temp(1:end-time_delay(i))];
    randn('state',0);
    y(i,:)=y(i,:)+sigma*randn(size(x));
end;
    y=sum(y,1);