obstack.c

linux平台中

     is sufficiently aligned.  */
  if (h->alignment_mask + 1 >= DEFAULT_ALIGNMENT)
    {
      for (i = obj_size / sizeof (COPYING_UNIT) - 1;
	   i >= 0; i--)
	((COPYING_UNIT *)new_chunk->contents)[i]
	  = ((COPYING_UNIT *)h->object_base)[i];
      /* We used to copy the odd few remaining bytes as one extra COPYING_UNIT,
	 but that can cross a page boundary on a machine
	 which does not do strict alignment for COPYING_UNITS.  */
      already = obj_size / sizeof (COPYING_UNIT) * sizeof (COPYING_UNIT);
    }
  else
    already = 0;
  /* Copy remaining bytes one by one.  */
  for (i = already; i < obj_size; i++)
    new_chunk->contents[i] = h->object_base[i];

  /* If the object just copied was the only data in OLD_CHUNK,
     free that chunk and remove it from the chain.
     But not if that chunk might contain an empty object.  */
  if (h->object_base == old_chunk->contents && ! h->maybe_empty_object)
    {
      new_chunk->prev = old_chunk->prev;
      CALL_FREEFUN (h, old_chunk);
    }

  h->object_base = new_chunk->contents;
  h->next_free = h->object_base + obj_size;
  /* The new chunk certainly contains no empty object yet.  */
  h->maybe_empty_object = 0;
}

/* Return nonzero if object OBJ has been allocated from obstack H.
   This is here for debugging.
   If you use it in a program, you are probably losing.  */

#if defined (__STDC__) && __STDC__
/* Suppress -Wmissing-prototypes warning.  We don't want to declare this in
   obstack.h because it is just for debugging.  */
int _obstack_allocated_p (struct obstack *h, POINTER obj);
#endif

int
_obstack_allocated_p (h, obj)
     struct obstack *h;
     POINTER obj;
{
  register struct _obstack_chunk *lp;	/* below addr of any objects in this chunk */
  register struct _obstack_chunk *plp;	/* point to previous chunk if any */

  lp = (h)->chunk;
  /* We use >= rather than > since the object cannot be exactly at
     the beginning of the chunk but might be an empty object exactly
     at the end of an adjacent chunk.  */
  while (lp != 0 && ((POINTER) lp >= obj || (POINTER) (lp)->limit < obj))
    {
      plp = lp->prev;
      lp = plp;
    }
  return lp != 0;
}

/* Free objects in obstack H, including OBJ and everything allocate
   more recently than OBJ.  If OBJ is zero, free everything in H.  */

#undef obstack_free

/* This function has two names with identical definitions.
   This is the first one, called from non-ANSI code.  */

void
_obstack_free (h, obj)
     struct obstack *h;
     POINTER obj;
{
  register struct _obstack_chunk *lp;	/* below addr of any objects in this chunk */
  register struct _obstack_chunk *plp;	/* point to previous chunk if any */

  lp = h->chunk;
  /* We use >= because there cannot be an object at the beginning of a chunk.
     But there can be an empty object at that address
     at the end of another chunk.  */
  while (lp != 0 && ((POINTER) lp >= obj || (POINTER) (lp)->limit < obj))
    {
      plp = lp->prev;
      CALL_FREEFUN (h, lp);
      lp = plp;
      /* If we switch chunks, we can't tell whether the new current
	 chunk contains an empty object, so assume that it may.  */
      h->maybe_empty_object = 1;
    }
  if (lp)
    {
      h->object_base = h->next_free = (char *) (obj);
      h->chunk_limit = lp->limit;
      h->chunk = lp;
    }
  else if (obj != 0)
    /* obj is not in any of the chunks! */
    abort ();
}

/* This function is used from ANSI code.  */

void
obstack_free (h, obj)
     struct obstack *h;
     POINTER obj;
{
  register struct _obstack_chunk *lp;	/* below addr of any objects in this chunk */
  register struct _obstack_chunk *plp;	/* point to previous chunk if any */

  lp = h->chunk;
  /* We use >= because there cannot be an object at the beginning of a chunk.
     But there can be an empty object at that address
     at the end of another chunk.  */
  while (lp != 0 && ((POINTER) lp >= obj || (POINTER) (lp)->limit < obj))
    {
      plp = lp->prev;
      CALL_FREEFUN (h, lp);
      lp = plp;
      /* If we switch chunks, we can't tell whether the new current
	 chunk contains an empty object, so assume that it may.  */
      h->maybe_empty_object = 1;
    }
  if (lp)
    {
      h->object_base = h->next_free = (char *) (obj);
      h->chunk_limit = lp->limit;
      h->chunk = lp;
    }
  else if (obj != 0)
    /* obj is not in any of the chunks! */
    abort ();
}

int
_obstack_memory_used (h)
     struct obstack *h;
{
  register struct _obstack_chunk* lp;
  register int nbytes = 0;

  for (lp = h->chunk; lp != 0; lp = lp->prev)
    {
      nbytes += lp->limit - (char *) lp;
    }
  return nbytes;
}

/* Define the error handler.  */
#ifndef _
# ifdef HAVE_LIBINTL_H
#  include <libintl.h>
#  ifndef _
#   define _(Str) gettext (Str)
#  endif
# else
#  define _(Str) (Str)
# endif
#endif
#if defined _LIBC && defined USE_IN_LIBIO
# include <libio/iolibio.h>
# define fputs(s, f) _IO_fputs (s, f)
#endif

static void
print_and_abort ()
{
  fputs (_("memory exhausted"), stderr);
  fputc ('\n', stderr);
  exit (obstack_exit_failure);
}

#if 0
/* These are now turned off because the applications do not use it
   and it uses bcopy via obstack_grow, which causes trouble on sysV.  */

/* Now define the functional versions of the obstack macros.
   Define them to simply use the corresponding macros to do the job.  */

#if defined (__STDC__) && __STDC__
/* These function definitions do not work with non-ANSI preprocessors;
   they won't pass through the macro names in parentheses.  */

/* The function names appear in parentheses in order to prevent
   the macro-definitions of the names from being expanded there.  */

POINTER (obstack_base) (obstack)
     struct obstack *obstack;
{
  return obstack_base (obstack);
}

POINTER (obstack_next_free) (obstack)
     struct obstack *obstack;
{
  return obstack_next_free (obstack);
}

int (obstack_object_size) (obstack)
     struct obstack *obstack;
{
  return obstack_object_size (obstack);
}

int (obstack_room) (obstack)
     struct obstack *obstack;
{
  return obstack_room (obstack);
}

int (obstack_make_room) (obstack, length)
     struct obstack *obstack;
     int length;
{
  return obstack_make_room (obstack, length);
}

void (obstack_grow) (obstack, pointer, length)
     struct obstack *obstack;
     POINTER pointer;
     int length;
{
  obstack_grow (obstack, pointer, length);
}

void (obstack_grow0) (obstack, pointer, length)
     struct obstack *obstack;
     POINTER pointer;
     int length;
{
  obstack_grow0 (obstack, pointer, length);
}

void (obstack_1grow) (obstack, character)
     struct obstack *obstack;
     int character;
{
  obstack_1grow (obstack, character);
}

void (obstack_blank) (obstack, length)
     struct obstack *obstack;
     int length;
{
  obstack_blank (obstack, length);
}

void (obstack_1grow_fast) (obstack, character)
     struct obstack *obstack;
     int character;
{
  obstack_1grow_fast (obstack, character);
}

void (obstack_blank_fast) (obstack, length)
     struct obstack *obstack;
     int length;
{
  obstack_blank_fast (obstack, length);
}

POINTER (obstack_finish) (obstack)
     struct obstack *obstack;
{
  return obstack_finish (obstack);
}

POINTER (obstack_alloc) (obstack, length)
     struct obstack *obstack;
     int length;
{
  return obstack_alloc (obstack, length);
}

POINTER (obstack_copy) (obstack, pointer, length)
     struct obstack *obstack;
     POINTER pointer;
     int length;
{
  return obstack_copy (obstack, pointer, length);
}

POINTER (obstack_copy0) (obstack, pointer, length)
     struct obstack *obstack;
     POINTER pointer;
     int length;
{
  return obstack_copy0 (obstack, pointer, length);
}

#endif /* __STDC__ */

#endif /* 0 */

#endif	/* !ELIDE_CODE */