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 </A>

<A HREF="CH15.5.htm#37555" CLASS="XRef">

Table&nbsp;15.6</A>

 shows specified maximum leakage currents of junction parasitic diodes as well as the leakage currents of the <A NAME="marker=161340">

 </A>

field transistors (the parasitic MOS transistors formed when poly crosses over the thick oxide, or field oxide) in a typical 0.5 <SPAN CLASS="Symbol">

m</SPAN>

m process. </P>

<TABLE>

<TR>

<TD ROWSPAN="1" COLSPAN="4">

<P CLASS="TableTitle">

<A NAME="pgfId=182781">

 </A>

TABLE&nbsp;15.6&nbsp;<A NAME="37555">

 </A>

Diffusion leakage currents (at 25 &#176;C) for a typical 0.5 <SPAN CLASS="Symbol">

m</SPAN>

m (<SPAN CLASS="Symbol">

l</SPAN>

 = 0.25 <SPAN CLASS="Symbol">

m</SPAN>

m) CMOS process.</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161352">

 </A>

<SPAN CLASS="TableHeads">

Junction</SPAN>

</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161354">

 </A>

<SPAN CLASS="TableHeads">

Diode type</SPAN>

</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableFirst">

<A NAME="pgfId=161356">

 </A>

<SPAN CLASS="TableHeads">

Leakage (max.)</SPAN>

</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableFirst">

<A NAME="pgfId=161358">

 </A>

<SPAN CLASS="TableHeads">

Unit</SPAN>

</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161360">

 </A>

<SPAN CLASS="Emphasis">

n</SPAN>

-diffusion/<SPAN CLASS="Emphasis">

p</SPAN>

-substrate</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161362">

 </A>

area</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161364">

 </A>

  0.6</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161366">

 </A>

fA <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

&#8211;2</SUP>

V<SUP CLASS="Superscript">

&#8211;1</SUP>

</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161368">

 </A>

<SPAN CLASS="Emphasis">

n</SPAN>

-diffusion/<SPAN CLASS="Emphasis">

p</SPAN>

-substrate</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161370">

 </A>

perimeter</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161372">

 </A>

  2.0</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161374">

 </A>

fA <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

&#8211;1</SUP>

V<SUP CLASS="Superscript">

&#8211;1</SUP>

</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161376">

 </A>

<SPAN CLASS="Emphasis">

p</SPAN>

-diffusion/<SPAN CLASS="Emphasis">

n</SPAN>

-well</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161378">

 </A>

area</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161380">

 </A>

 0.6</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161382">

 </A>

fA <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

&#8211;2</SUP>

V<SUP CLASS="Superscript">

&#8211;1</SUP>

</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161384">

 </A>

<SPAN CLASS="Emphasis">

p</SPAN>

-diff/<SPAN CLASS="Emphasis">

n</SPAN>

-well</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161386">

 </A>

perimeter</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161388">

 </A>

  3.0</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161390">

 </A>

fA <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

&#8211;1</SUP>

V<SUP CLASS="Superscript">

&#8211;1</SUP>

</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161392">

 </A>

<SPAN CLASS="Emphasis">

n</SPAN>

-well /<SPAN CLASS="Emphasis">

p</SPAN>

-substrate</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161394">

 </A>

area</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161396">

 </A>

  1.0</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161398">

 </A>

fA <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

&#8211;2</SUP>

V<SUP CLASS="Superscript">

&#8211;1</SUP>

</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161400">

 </A>

Field NMOS transistor</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161402">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161404">

 </A>

100</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161406">

 </A>

fA <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

&#8211;1</SUP>

</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161408">

 </A>

Field PMOS transistor</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableLeft">

<A NAME="pgfId=161410">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161412">

 </A>

  30</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="Table">

<A NAME="pgfId=161414">

 </A>

fA <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

&#8211;1</SUP>

</P>

</TD>

</TR>

</TABLE>

<P CLASS="Body">

<A NAME="pgfId=161415">

 </A>

For example, if we have an <SPAN CLASS="EmphasisPrefix">

n</SPAN>

-diffusion region at a potential of 3.3 V that is 10<SPAN CLASS="Symbol">

 m</SPAN>

m by 4<SPAN CLASS="Symbol">

  m</SPAN>

m in size, the parasitic leakage current due to the area diode would be  </P>

<TABLE>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnRight">

<A NAME="pgfId=203650">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203652">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnLeft">

<A NAME="pgfId=203654">

 </A>

40 <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

2</SUP>

 <SPAN CLASS="Symbol">

&#165;</SPAN>

 3.3 V <SPAN CLASS="Symbol">

&#165;</SPAN>

 0.6 fA <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

&#8211;2</SUP>

V<SUP CLASS="Superscript">

&#8211;1</SUP>

</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203656">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqn">

<A NAME="pgfId=203658">

 </A>

&nbsp;</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnRight">

<A NAME="pgfId=203666">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203668">

 </A>

=</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnLeft">

<A NAME="pgfId=203670">

 </A>

(40) (3.3) (0.6 <SPAN CLASS="Symbol">

&#165;</SPAN>

 10<SUP CLASS="Superscript">

&#8211;15</SUP>

)</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203672">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqn">

<A NAME="pgfId=203674">

 </A>

&nbsp;</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnRight">

<A NAME="pgfId=203676">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203678">

 </A>

=</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnLeft">

<A NAME="pgfId=203680">

 </A>

7.92 <SPAN CLASS="Symbol">

&#165;</SPAN>

 10<SUP CLASS="Superscript">

&#8211;14</SUP>

 A ,</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203682">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqn">

<A NAME="pgfId=203684">

 </A>

&nbsp;</P>

</TD>

</TR>

</TABLE>

<P CLASS="BodyAfterHead">

<A NAME="pgfId=161420">

 </A>

or approximately 80 fA. </P>

<P CLASS="Body">

<A NAME="pgfId=192041">

 </A>

The perimeter of this drain region is 28 <SPAN CLASS="Symbol">

m</SPAN>

m, so that the leakage current due to the perimeter diode is  </P>

<TABLE>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnRight">

<A NAME="pgfId=203688">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203690">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnLeft">

<A NAME="pgfId=203692">

 </A>

28 <SPAN CLASS="Symbol">

m</SPAN>

m <SPAN CLASS="Symbol">

&#165;</SPAN>

 3.3 V <SPAN CLASS="Symbol">

&#165;</SPAN>

 2.0 fA <SPAN CLASS="Symbol">

m</SPAN>

m<SUP CLASS="Superscript">

&#8211;1</SUP>

V<SUP CLASS="Superscript">

&#8211;1</SUP>

</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203694">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqn">

<A NAME="pgfId=203696">

 </A>

&nbsp;</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnRight">

<A NAME="pgfId=203698">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203700">

 </A>

=</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnLeft">

<A NAME="pgfId=203702">

 </A>

(28) (3.3) (2.0 <SPAN CLASS="Symbol">

&#165;</SPAN>

 10<SUP CLASS="Superscript">

&#8211;15</SUP>

)</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203704">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqn">

<A NAME="pgfId=203706">

 </A>

&nbsp;</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnRight">

<A NAME="pgfId=203708">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203710">

 </A>

=</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnLeft">

<A NAME="pgfId=203712">

 </A>

2.848 <SPAN CLASS="Symbol">

&#165;</SPAN>

 10<SUP CLASS="Superscript">

&#8211;13</SUP>

 A ,</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203714">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqn">

<A NAME="pgfId=203716">

 </A>

&nbsp;</P>

</TD>

</TR>

</TABLE>

<P CLASS="BodyAfterHead">

<A NAME="pgfId=161426">

 </A>

or approximately 0.2 pA, over twice as large as the area-diode leakage current.</P>

<P CLASS="Body">

<A NAME="pgfId=161427">

 </A>

As a very rough estimate, if we have 100,000 transistors each with a source and a drain 10<SPAN CLASS="Symbol">

  m</SPAN>

m by 4 <SPAN CLASS="Symbol">

m</SPAN>

m, and half of them are biased at 3.3 V, then the total leakage current would be  </P>

<TABLE>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnRight">

<A NAME="pgfId=203756">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203758">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnLeft">

<A NAME="pgfId=203760">

 </A>

(100 <SPAN CLASS="Symbol">

&#165;</SPAN>

 10<SUP CLASS="Superscript">

5</SUP>

) (2) (0.5) (280 <SPAN CLASS="Symbol">

&#165;</SPAN>

 10<SUP CLASS="Superscript">

&#8211;15</SUP>

)</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203762">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqn">

<A NAME="pgfId=203764">

 </A>

&nbsp;</P>

</TD>

</TR>

<TR>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnRight">

<A NAME="pgfId=203766">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203768">

 </A>

=</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnLeft">

<A NAME="pgfId=203770">

 </A>

2.8 <SPAN CLASS="Symbol">

&#165;</SPAN>

 10<SUP CLASS="Superscript">

&#8211;6</SUP>

 A ,</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnCenter">

<A NAME="pgfId=203772">

 </A>

&nbsp;</P>

</TD>

<TD ROWSPAN="1" COLSPAN="1">

<P CLASS="TableEqnNumber">

<A NAME="pgfId=203774">

 </A>

(15.12)</P>

</TD>

</TR>

</TABLE>

<P CLASS="BodyAfterHead">

<A NAME="pgfId=161432">

 </A>

or approximately 3 <SPAN CLASS="Symbol">

m</SPAN>

A. This is the same order of magnitude (a few microamperes) as the quiescent leakage current, <SPAN CLASS="EquationVariables">

I</SPAN>

<SUB CLASS="SubscriptVariable">

DDQ</SUB>

, that we expect to measure when we test an ASIC with power applied, but with no signal activity. A measurement of more current than this in a nonactive CMOS ASIC indicates a problem with the chip manufacture or the design. We use this measurement to test an ASIC using an <A NAME="marker=182785">

 </A>

IDDQ test.</P>

</DIV>

<HR><P>[&nbsp;<A HREF="CH15.htm">Chapter&nbsp;start</A>&nbsp;]&nbsp;[&nbsp;<A HREF="CH15.4.htm">Previous&nbsp;page</A>&nbsp;]&nbsp;[&nbsp;<A HREF="CH15.6.htm">Next&nbsp;page</A>&nbsp;]</P></BODY>



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