ch27-17.c

C语言程序设计上机指导与练习 冶金工业出版社 刘怀亮

#include <stdio.h>
int a[3000],cnt=0;
double pjz1=0.0,pjz2=0.0;

void readDat()
{
   int i;
   for(i=0;i<3000;i++) a[i]=i+4001;
}
void writeDat()
{
   FILE *fp;
   fp=fopen("out.dat","w");
   fprintf(fp,"%d\n%7.2f\n%7.2f\n",cnt,pjz1,pjz2);
   fclose(fp);
}
jsValue()
{
   int i,qw,bw,sw,gw,n=0;
   for(i=0;i<3000;i++)
   {
      qw=a[i]/1000;    
      bw=a[i]%1000/100;
      sw=a[i]%100/10;  
      gw=a[i]%10;
      if(qw-bw-sw-gw>0) 
      {
         cnt++;
         pjz1+=a[i];
      }
      else 
      {
         n++;
         pjz2+=a[i];
      }
   }
   if(cnt==0) pjz1=0;
   else pjz1/=cnt;
   if(n==0) pjz2=0;
   else pjz2/=n;
} 
main()
{
   readDat();
   jsValue();
   writeDat();
   printf("cnt=%d\n满足条件的平均值pzj1=%7.2f\n不满足条件的平均值pzj2=%7.2f\n",
      cnt,pjz1,pjz2);
}