8-14.c

C语言程序设计及应用习题解析与上机指导 冶金工业出版社 谢乐军

main()
{int i,j,k;
 int min,t;
 int a[9][8]={{1,19,81,89,99,98,87},{2,16,89,90,95,80,90},{3,17,91,77,88,95,78},
{4,18,79,84,95,93,96},{5,15,95,92,98,99,93},{6,17,78,88,85,86,80},
{7,14,91,85,94,82,88},{8,15,90,92,94,90,95},{9,16,75,85,87,94,90}};
 float ave;
  for(i=0;i<=8;i++)
   for(j=2;j<=6;j++)
     a[i][7]=a[i][7]+a[i][j];
 printf("the student's scores:\n");
 for(i=0;i<=8;i++)
   {for(j=0;j<=7;j++)
       printf("%5d",a[i][j]);
    printf("\n");
   }
 for(i=0;i<=7;i++)
   {min=i;
    for(j=i+1;j<=8;j++)
      if(a[min][7]<a[j][7]) min=j;
    for(j=0;j<=7;j++)
    {t=a[i][j];a[i][j]=a[min][j];a[min][j]=t;}
   }
 printf("the sorted scores:\n");
 for(i=0;i<=8;i++)
   {for(j=0;j<=7;j++)
       printf("%5d",a[i][j]);
    printf("\n");
   }
 ave=(float)a[6][8]/5;
 printf(“%.2f”,ave);
}