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📄 where3.test

📁 嵌入式数据库SQLITE,含移植到ARM_LINUX的说明
💻 TEST
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# 2006 January 31## The author disclaims copyright to this source code.  In place of# a legal notice, here is a blessing:##    May you do good and not evil.#    May you find forgiveness for yourself and forgive others.#    May you share freely, never taking more than you give.##***********************************************************************# This file implements regression tests for SQLite library.  The# focus of this file is testing the join reordering optimization# in cases that include a LEFT JOIN.## $Id: where3.test,v 1.2 2006/06/06 11:45:55 drh Exp $set testdir [file dirname $argv0]source $testdir/tester.tcl# The following is from ticket #1652.## A comma join then a left outer join:  A,B left join C.# Arrange indices so that the B table is chosen to go first.# Also put an index on C, but make sure that A is chosen before C.#do_test where3-1.1 {  execsql {    CREATE TABLE t1(a, b);    CREATE TABLE t2(p, q);    CREATE TABLE t3(x, y);        INSERT INTO t1 VALUES(111,'one');    INSERT INTO t1 VALUES(222,'two');    INSERT INTO t1 VALUES(333,'three');        INSERT INTO t2 VALUES(1,111);    INSERT INTO t2 VALUES(2,222);    INSERT INTO t2 VALUES(4,444);    CREATE INDEX t2i1 ON t2(p);        INSERT INTO t3 VALUES(999,'nine');    CREATE INDEX t3i1 ON t3(x);        SELECT * FROM t1, t2 LEFT JOIN t3 ON q=x WHERE p=2 AND a=q;  }} {222 two 2 222 {} {}}# Ticket #1830## This is similar to the above but with the LEFT JOIN on the# other side.#do_test where3-1.2 {  execsql {    CREATE TABLE parent1(parent1key, child1key, Child2key, child3key);    CREATE TABLE child1 ( child1key NVARCHAR, value NVARCHAR );    CREATE UNIQUE INDEX PKIDXChild1 ON child1 ( child1key );    CREATE TABLE child2 ( child2key NVARCHAR, value NVARCHAR );    INSERT INTO parent1(parent1key,child1key,child2key)       VALUES ( 1, 'C1.1', 'C2.1' );    INSERT INTO child1 ( child1key, value ) VALUES ( 'C1.1', 'Value for C1.1' );    INSERT INTO child2 ( child2key, value ) VALUES ( 'C2.1', 'Value for C2.1' );    INSERT INTO parent1 ( parent1key, child1key, child2key )       VALUES ( 2, 'C1.2', 'C2.2' );    INSERT INTO child2 ( child2key, value ) VALUES ( 'C2.2', 'Value for C2.2' );    INSERT INTO parent1 ( parent1key, child1key, child2key )       VALUES ( 3, 'C1.3', 'C2.3' );    INSERT INTO child1 ( child1key, value ) VALUES ( 'C1.3', 'Value for C1.3' );    INSERT INTO child2 ( child2key, value ) VALUES ( 'C2.3', 'Value for C2.3' );    SELECT parent1.parent1key, child1.value, child2.value    FROM parent1    LEFT OUTER JOIN child1 ON child1.child1key = parent1.child1key    INNER JOIN child2 ON child2.child2key = parent1.child2key;  }} {1 {Value for C1.1} {Value for C2.1} 2 {} {Value for C2.2} 3 {Value for C1.3} {Value for C2.3}}finish_test

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