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📄 constantexpression.sql

📁 derby database source code.good for you.
💻 SQL
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-- tests for constant expression evaluationautocommit off;-- create and populate a tablecreate table t1(c1 int);insert into t1 values 1, 2, 3;-- false constant expressionsselect * from t1 where 1 <> 1;select * from t1 where 1 = 1 and 1 = 0;select * from t1 where 1 = (2 + 3 - 2);select * from t1 where (case when 1 = 1 then 0 else 1 end) = 1;select * from t1 where 1 in (2, 3, 4);select * from t1 where 1 between 2 and 3;prepare p1 as 'select * from t1 where ? = 1';prepare p2 as 'select * from t1 where cast(? as int) = 1';execute p1 using 'values 0';execute p2 using 'values 0';-- true constant expressionsselect * from t1 where 1 = 1;select * from t1 where 1 = 0 or 1 = 1;select * from t1 where 1 + 2 = (2 + 3 - 2);select * from t1 where (case when 1 = 1 then 1 else 0 end) = 1;select * from t1 where 1 in (2, 3, 4, 4, 3, 2, 1);select * from t1 where 1 + 1 between 0 and 3;execute p1 using 'values 1';execute p2 using 'values 1';-- clean updrop table t1;

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