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📄 dml158.sql

📁 derby database source code.good for you.
💻 SQL
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AUTOCOMMIT OFF;-- MODULE  DML158  -- SQL Test Suite, V6.0, Interactive SQL, dml158.sql-- 59-byte ID-- TEd Version #-- AUTHORIZATION HU   set schema HU;--O   SELECT USER FROM HU.ECCO;  VALUES USER;-- RERUN if USER value does not match preceding AUTHORIZATION comment   ROLLBACK WORK;-- date_time print-- TEST:0857 <join condition> set function, outer reference! Error   DELETE FROM WORKS     WHERE EXISTS      (SELECT * FROM PROJ JOIN STAFF      ON PROJ.CITY <> STAFF.CITY      AND EMPNUM = WORKS.EMPNUM      AND PNUM = WORKS.PNUM);-- PASS:0857 If ERROR OR SQLSTATE = 42X04   SELECT EMPNUM, PNUM FROM WORKS       ORDER BY EMPNUM, PNUM;-- PASS:0857 If 12 rows are returned in the following order?--                 empnum    pnum--                 ======    ====-- PASS:0857 If    E1        P1  ?-- PASS:0857 If    E1        P2  ?-- PASS:0857 If    E1        P3  ?-- PASS:0857 If    E1        P4  ?-- PASS:0857 If    E1        P5  ?-- PASS:0857 If    E1        P6  ?-- PASS:0857 If    E2        P1  ?-- PASS:0857 If    E2        P2  ?-- PASS:0857 If    E3        P2  ?-- PASS:0857 If    E4        P2  ?-- PASS:0857 If    E4        P4  ?-- PASS:0857 If    E4        P5  ?   ROLLBACK WORK;   SELECT EMPNUM, SUM (HOURS) FROM WORKS OWORKS       GROUP BY EMPNUM       HAVING EMPNUM IN (--O       SELECT WORKS.EMPNUM FROM WORKS JOIN STAFF--O       ON WORKS.EMPNUM = STAFF.EMPNUM       SELECT a.EMPNUM FROM WORKS a, STAFF       where a.EMPNUM = STAFF.EMPNUM--O       AND HOURS < SUM (OWORKS.HOURS) / 3       AND a.HOURS < (select SUM (b.HOURS) / 3 from works b  where a.empnum = b.empnum)       AND GRADE > 10)       ORDER BY EMPNUM;-- PASS:0857 If 2 rows are returned in the following order?--               empnum    sum(hours)--               ======    ==========-- PASS:0857 If  E1        184       ?-- PASS:0857 If  E4        140       ?   SELECT EMPNUM, SUM (HOURS) FROM WORKS OWORKS       GROUP BY EMPNUM       HAVING EMPNUM IN (--O       SELECT WORKS.EMPNUM FROM WORKS JOIN STAFF--O       ON WORKS.EMPNUM = STAFF.EMPNUM       SELECT a.EMPNUM FROM WORKS a, STAFF       where a.EMPNUM = STAFF.EMPNUM--O       AND HOURS >= 10 + AVG (OWORKS.HOURS)       AND a.HOURS >= (select 10 + AVG (b.HOURS) from works b where a.empnum = b.empnum)       AND CITY = 'Deale')       ORDER BY EMPNUM;-- PASS:0857 If 2 rows are returned in the following order?--               empnum    sum(hours)--               ======    ==========-- PASS:0857 If  E1        184       ?-- PASS:0857 If  E4        140       ?   COMMIT WORK;-- END TEST >>> 0857 <<< END TEST-- *********************************************-- *************************************************////END-OF-MODULE

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