⭐ 欢迎来到虫虫下载站! | 📦 资源下载 📁 资源专辑 ℹ️ 关于我们
⭐ 虫虫下载站

📄 dml075.sql

📁 derby database source code.good for you.
💻 SQL
字号:
AUTOCOMMIT OFF;-- MODULE DML075-- SQL Test Suite, V6.0, Interactive SQL, dml075.sql-- 59-byte ID-- TEd Version #-- AUTHORIZATION HU   set schema HU;--O   SELECT USER FROM HU.ECCO;  VALUES USER;-- RERUN if USER value does not match preceding AUTHORIZATION comment-- date_time print-- TEST:0431 Redundant rows in IN subquery!--O   SELECT COUNT (*) FROM STAFF   SELECT * FROM STAFF       WHERE EMPNUM IN            (SELECT EMPNUM FROM WORKS);-- PASS:0431 If count = 4?   INSERT INTO STAFF1       SELECT * FROM STAFF;--O   SELECT COUNT (*) FROM STAFF1   SELECT * FROM STAFF1       WHERE EMPNUM IN            (SELECT EMPNUM FROM WORKS);-- PASS:0431 If count = 4?   ROLLBACK WORK;-- END TEST >>> 0431 <<< END TEST-- *************************************************************-- TEST:0432 Unknown comparison predicate in ALL, SOME, ANY!-- setupUPDATE PROJ SET CITY = NULL   WHERE PNUM = 'P3';--OSELECT COUNT(*)SELECT *  FROM STAFF  WHERE CITY = ALL (SELECT CITY                   FROM PROJ                   WHERE PNAME = 'SDP');-- PASS:0432 If count = 0?--OSELECT COUNT(*)SELECT *  FROM STAFF  WHERE CITY <> ALL (SELECT CITY                     FROM PROJ                    WHERE PNAME = 'SDP');-- PASS:0432 If count = 0?--OSELECT COUNT(*)SELECT *  FROM STAFF  WHERE CITY = ANY (SELECT CITY                       FROM PROJ                   WHERE PNAME = 'SDP');-- PASS:0432 If count = 2?--OSELECT COUNT(*)SELECT *  FROM STAFF  WHERE CITY <> ANY (SELECT CITY                     FROM PROJ                     WHERE PNAME = 'SDP');-- PASS:0432 If count = 3?--OSELECT COUNT(*)SELECT *  FROM STAFF  WHERE CITY = SOME (SELECT CITY                     FROM PROJ                     WHERE PNAME = 'SDP');-- PASS:0432 If count = 2?--OSELECT COUNT(*)SELECT *  FROM STAFF  WHERE CITY <> SOME (SELECT CITY                      FROM PROJ                      WHERE PNAME = 'SDP');-- PASS:0432 If count = 3?   ROLLBACK WORK;-- END TEST >>> 0432 <<< END TEST-- *************************************************************-- TEST:0433 Empty subquery in ALL, SOME, ANY!--O   SELECT COUNT(*) FROM PROJ   SELECT * FROM PROJ        WHERE PNUM = ALL (SELECT PNUM                          FROM WORKS WHERE EMPNUM = 'E8');-- PASS:0433 If count = 6?--O   SELECT COUNT(*) FROM PROJ   SELECT * FROM PROJ        WHERE PNUM <> ALL (SELECT PNUM                          FROM WORKS WHERE EMPNUM = 'E8');-- PASS:0433 If count = 6?--O   SELECT COUNT(*) FROM PROJ   SELECT * FROM PROJ        WHERE PNUM = ANY (SELECT PNUM                          FROM WORKS WHERE EMPNUM = 'E8');-- PASS:0433 If count = 0?--O   SELECT COUNT(*) FROM PROJ   SELECT * FROM PROJ        WHERE PNUM <> ANY (SELECT PNUM                          FROM WORKS WHERE EMPNUM = 'E8');-- PASS:0433 If count = 0?--O   SELECT COUNT(*) FROM PROJ   SELECT * FROM PROJ        WHERE PNUM = SOME (SELECT PNUM                          FROM WORKS WHERE EMPNUM = 'E8');-- PASS:0433 If count = 0?--O   SELECT COUNT(*) FROM PROJ   SELECT * FROM PROJ        WHERE PNUM <> SOME (SELECT PNUM                          FROM WORKS WHERE EMPNUM = 'E8');-- PASS:0433 If count = 0?-- END TEST >>> 0433 <<< END TEST-- *************************************************************-- TEST:0434 GROUP BY with HAVING EXISTS-correlated set function!   SELECT PNUM, SUM(HOURS) FROM WORKS c          GROUP BY PNUM--O          HAVING EXISTS (SELECT PNAME FROM PROJ--O                         WHERE PROJ.PNUM = WORKS.PNUM AND          HAVING EXISTS (SELECT PNAME FROM PROJ, works a                         WHERE PROJ.PNUM = a.PNUM AND--O                               SUM(WORKS.HOURS) > PROJ.BUDGET / 200);                         PROJ.BUDGET / 200 < (select sum(hours) from works b			  where a.pnum = b.pnum			  and a.pnum = c.pnum));-- PASS:0434 If 2 rows selected with values (in any order):?-- PASS:0434 PNUM = 'P1', SUM(HOURS) = 80?-- PASS:0434 PNUM = 'P5', SUM(HOURS) = 92?-- END TEST >>> 0434 <<< END TEST-- *************************************************************-- TEST:0442 DISTINCT with GROUP BY, HAVING!   SELECT PTYPE, CITY FROM PROJ          GROUP BY PTYPE, CITY          HAVING AVG(BUDGET) > 21000;-- PASS:0442 If 3 rows selected with PTYPE/CITY values(in any order):?-- PASS:0442 Code/Vienna, Design/Deale, Test/Tampa?   SELECT DISTINCT PTYPE, CITY FROM PROJ          GROUP BY PTYPE, CITY          HAVING AVG(BUDGET) > 21000;-- PASS:0442 If 3 rows selected with PTYPE/CITY values(in any order):?-- PASS:0442 Code/Vienna, Design/Deale, Test/Tampa?   SELECT DISTINCT SUM(BUDGET) FROM PROJ          GROUP BY PTYPE, CITY          HAVING AVG(BUDGET) > 21000;-- PASS:0442 If 2 rows selected (in any order):?-- PASS:0442 with SUM(BUDGET) values 30000 and 80000?-- END TEST >>> 0442 <<< END TEST-- *************************************************////END-OF-MODULE

⌨️ 快捷键说明

复制代码 Ctrl + C
搜索代码 Ctrl + F
全屏模式 F11
切换主题 Ctrl + Shift + D
显示快捷键 ?
增大字号 Ctrl + =
减小字号 Ctrl + -