📄 2-18.txt
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例2.18 引用是一种隐式指针
#include <iostream.h>
void main()
{ int i=15;
int *iptr=&i;
int &rptr=i;
cout<<"i is "<<i<<endl;
cout<<"*iptr is "<<*iptr<<endl;
cout<<"rptr is "<<rptr<<endl;
i=29;
cout<<"After changing i to 29:\n";
cout<<"i is "<<i<<endl;
cout<<"*iptr is "<<*iptr<<endl;
cout<<"rptr is "<<rptr<<endl;
}
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