fun_post.php

我不介意你怎么用这个程序

<?php
if(isset($_SERVER["HTTP_REFERER"]))
{
	$server_name = $_SERVER["SERVER_NAME"];
	$url = parse_url($_SERVER["HTTP_REFERER"]);
	if($url["host"]!=$server_name)
	{
		echo "<script language='javascript'>window.alert('表单提交错误，请勿使用任何外部程序提交表单！');window.opener=self;window.close();</script>";
		exit();
	}
}
?>