📄 demonewton.m
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function x = demoNewton(x0,n)
% demoNewton Use Newton's method to find the root of f(x) = x - x^(1/3) - 2
%
% Synopsis: x = demoNewton(x0)
% x = demoNewton(x0,n)
%
% Input: x0 = initial guess
% n = (optional) number of iterations, Default: n = 5
%
% Output x = estimate of the root
if nargin<2, n=5; end % Default number of iterations
x = x0; % Initial guess
fprintf(' k f(x) dfdx x(k+1)\n');
for k=1:n
f = x - x.^(1/3) - 2;
dfdx = 1 - (1/3)*x.^(-2/3);
x = x - f/dfdx;
fprintf('%3d %12.3e %12.3e %18.15f\n',k-1,f,dfdx,x);
end
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