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📄 test5_am.c

📁 mpi并行计算的c++代码 可用vc或gcc编译通过 可以用来搭建并行计算试验环境
💻 C
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/* -*- Mode: C; c-basic-offset:4 ; -*- *//* *  (C) 2001 by Argonne National Laboratory. *      See COPYRIGHT in top-level directory. */#include "mpi.h" #include "stdio.h"#include "mpitest.h"/* tests a series of Gets. Run on 2 processes. *//* same as test5.c but uses alloc_mem */#define SIZE 2000int main(int argc, char *argv[]) { /*    int rank, nprocs, i, A[SIZE], B[SIZE]; */    int rank, nprocs, i, *A, *B;    MPI_Win win;    int errs = 0;     MTest_Init(&argc,&argv);     MPI_Comm_size(MPI_COMM_WORLD,&nprocs);     MPI_Comm_rank(MPI_COMM_WORLD, &rank);       if (nprocs != 2) {        printf("Run this program with 2 processes\n");        MPI_Abort(MPI_COMM_WORLD,1);    }    i = MPI_Alloc_mem(SIZE * sizeof(int), MPI_INFO_NULL, &A);    if (i) {        printf("Can't allocate memory in test program\n");        MPI_Abort(MPI_COMM_WORLD, 1);    }    i = MPI_Alloc_mem(SIZE * sizeof(int), MPI_INFO_NULL, &B);    if (i) {        printf("Can't allocate memory in test program\n");        MPI_Abort(MPI_COMM_WORLD, 1);    }        if (rank == 0) {        for (i=0; i<SIZE; i++)            B[i] = 500 + i;        MPI_Win_create(B, SIZE*sizeof(int), sizeof(int), MPI_INFO_NULL,                        MPI_COMM_WORLD, &win);         MPI_Win_fence(0, win);         for (i=0; i<SIZE; i++) {            A[i] = i+100;            MPI_Get(&A[i], 1, MPI_INT, 1, i, 1, MPI_INT, win);        }        MPI_Win_fence(0, win);         for (i=0; i<SIZE; i++)            if (A[i] != 1000 + i) {                printf("Rank 0: A[%d] is %d, should be %d\n", i, A[i], 1000+i);                errs++;            }    }    if (rank == 1) {        for (i=0; i<SIZE; i++)            A[i] = 1000 + i;        MPI_Win_create(A, SIZE*sizeof(int), sizeof(int), MPI_INFO_NULL,                    MPI_COMM_WORLD, &win);         MPI_Win_fence(0, win);         for (i=0; i<SIZE; i++) {            B[i] = i+200;            MPI_Get(&B[i], 1, MPI_INT, 0, i, 1, MPI_INT, win);        }        MPI_Win_fence(0, win);         for (i=0; i<SIZE; i++)            if (B[i] != 500 + i) {                printf("Rank 1: B[%d] is %d, should be %d\n", i, B[i], 500+i);                errs++;            }    }    MPI_Win_free(&win);     MPI_Free_mem(A);    MPI_Free_mem(B);    MTest_Finalize(errs);    MPI_Finalize();     return 0; } 

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