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📄 transpose2.c

📁 mpi并行计算的c++代码 可用vc或gcc编译通过 可以用来搭建并行计算试验环境
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/* -*- Mode: C; c-basic-offset:4 ; -*- *//* *  (C) 2001 by Argonne National Laboratory. *      See COPYRIGHT in top-level directory. */#include "mpi.h" #include "stdio.h"#include "mpitest.h"/* transposes a matrix using put, fence, and derived   datatypes. Uses vector and struct (Example 3.33 from MPI 1.1   Standard). We could use vector and type_create_resized instead. Run   on 2 processes */ #define NROWS 100#define NCOLS 100int main(int argc, char *argv[]) {     int rank, nprocs, A[NROWS][NCOLS], i, j, blocklen[2];    MPI_Aint disp[2];    MPI_Win win;    MPI_Datatype column, column1, type[2];    int errs=0;     MTest_Init(&argc,&argv);     MPI_Comm_size(MPI_COMM_WORLD,&nprocs);     MPI_Comm_rank(MPI_COMM_WORLD,&rank);     if (nprocs != 2)    {        printf("Run this program with 2 processes\n");        MPI_Abort(MPI_COMM_WORLD,1);    }    if (rank == 0)    {        for (i=0; i<NROWS; i++)            for (j=0; j<NCOLS; j++)                A[i][j] = i*NCOLS + j;        /* create datatype for one column */        MPI_Type_vector(NROWS, 1, NCOLS, MPI_INT, &column);         /* create datatype for one column, with the extent of one           integer. we could use type_create_resized instead. */        disp[0] = 0;        disp[1] = sizeof(int);        type[0]  = column;        type[1]  = MPI_UB;        blocklen[0]  = 1;        blocklen[1]  = 1;         MPI_Type_struct(2, blocklen, disp, type, &column1);        MPI_Type_commit(&column1);         MPI_Win_create(NULL, 0, 1, MPI_INFO_NULL, MPI_COMM_WORLD, &win);         MPI_Win_fence(0, win);         MPI_Put(A, NROWS*NCOLS, MPI_INT, 1, 0, NCOLS, column1, win);        MPI_Type_free(&column);        MPI_Type_free(&column1);        MPI_Win_fence(0, win);     }            else    { /* rank = 1 */        for (i=0; i<NROWS; i++)             for (j=0; j<NCOLS; j++)                A[i][j] = -1;        MPI_Win_create(A, NROWS*NCOLS*sizeof(int), sizeof(int), MPI_INFO_NULL,                        MPI_COMM_WORLD, &win);         MPI_Win_fence(0, win);         MPI_Win_fence(0, win);         for (j=0; j<NCOLS; j++)	{            for (i=0; i<NROWS; i++)	    {                if (A[j][i] != i*NCOLS + j)		{		    if (errs < 50)		    {			printf("Error: A[%d][%d]=%d should be %d\n", j, i,			    A[j][i], i*NCOLS + j);		    }                    errs++;                }	    }	}	if (errs >= 50)	{	    printf("Total number of errors: %d\n", errs);	}    }    MPI_Win_free(&win);     MTest_Finalize(errs);    MPI_Finalize();     return 0; } 

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