6priority.c
来自「结合三星的4510ARM处理器 和VXworks 操作系统,的几个源程序,有助于」· C语言 代码 · 共 83 行
C
83 行
/*256个优先级,0-255,高-低,taskPrioritySet()*/
#include "vxWorks.h"
#include "taskLib.h"
#include "logLib.h"
void taskOne(void);
void taskTwo(void);
void taskThree(void);
#define ITER1 100
#define ITER2 1
#define LONG_TIME 1000000
#define HIGH 100
#define MID 101
#define LOW 102
void sched()
{
printf("\n\n\n\n\n");
if(taskSpawn("task1",LOW,0x100,20000,taskOne,0,0,0,0,0,0,0,0,0,0)==ERROR)
printf("taskSpawn task1 failed\n ");
if(taskSpawn("task2",MID,0x100,20000,taskTwo,0,0,0,0,0,0,0,0,0,0)==ERROR)
printf("taskSpawn task2 failed\n ");
if(taskSpawn("task3",HIGH,0x100,20000,taskThree,0,0,0,0,0,0,0,0,0,0)==ERROR)
printf("taskSpawn task3 failed\n ");
}
void taskOne()
{
int i,j;
for(i=0;i<ITER1;i++)
{
for(j=0;j<ITER2;j++)
logMsg("\n",0,0,0,0,0,0);
for(j=0;j<LONG_TIME;j++);
}
}
void taskTwo()
{
int i,j;
for(i=0;i<ITER1;i++)
{
for(j=0;j<ITER2;j++)
logMsg("\n",0,0,0,0,0,0);
for(j=0;j<LONG_TIME;j++);
}
}
void taskThree()
{
int i,j;
for(i=0;i<ITER1;i++)
{
for(j=0;j<ITER2;j++)
logMsg("\n",0,0,0,0,0,0);
for(j=0;j<LONG_TIME;j++);
}
}
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