📄 longsub.prg
字号:
* longsub.prg
* 长减法
* 注意:此程序未考虑最高位的借位问题,
* 因为这实际不可能发生
parameters a,b
private except eachlen,alllen
*eachlen=10
*alllen=len(a)
n=alllen/eachlen
c=""
jiewei=0
for i=1 to n step 1
*@ 8,10 say "longsub减法已做"+str(i)+"遍"
point1=alllen-i*eachlen+1
sub_a=substr(a,point1,eachlen)
sub_b=substr(b,point1,eachlen)
if sub_a>=sub_b
num_c=val(sub_a)-val(sub_b)-jiewei
jiewei=0
else
num_c=10**eachlen+val(sub_a)-val(sub_b)-jiewei
jiewei=1
endif
sub_c=str(num_c,eachlen+1)
sub_c=chrtran(sub_c," ","0")
sub_c=right(sub_c,eachlen)
c=sub_c+c
next i
return c
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