📄 ftbbox.c
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static void BBox_Cubic_Check( FT_Pos y1, FT_Pos y2, FT_Pos y3, FT_Pos y4, FT_Pos* min, FT_Pos* max ) { /* always compare first and last points */ if ( y1 < *min ) *min = y1; else if ( y1 > *max ) *max = y1; if ( y4 < *min ) *min = y4; else if ( y4 > *max ) *max = y4; /* now, try to see if there are split points here */ if ( y1 <= y4 ) { /* flat or ascending arc test */ if ( y1 <= y2 && y2 <= y4 && y1 <= y3 && y3 <= y4 ) return; } else /* y1 > y4 */ { /* descending arc test */ if ( y1 >= y2 && y2 >= y4 && y1 >= y3 && y3 >= y4 ) return; } /* There are some split points. Find them. */ { FT_Pos a = y4 - 3*y3 + 3*y2 - y1; FT_Pos b = y3 - 2*y2 + y1; FT_Pos c = y2 - y1; FT_Pos d; FT_Fixed t; /* We need to solve `ax^2+2bx+c' here, without floating points! */ /* The trick is to normalize to a different representation in order */ /* to use our 16.16 fixed point routines. */ /* */ /* We compute FT_MulFix(b,b) and FT_MulFix(a,c) after normalization. */ /* These values must fit into a single 16.16 value. */ /* */ /* We normalize a, b, and c to `8.16' fixed float values to ensure */ /* that its product is held in a `16.16' value. */ { FT_ULong t1, t2; int shift = 0; /* The following computation is based on the fact that for */ /* any value `y', if `n' is the position of the most */ /* significant bit of `abs(y)' (starting from 0 for the */ /* least significant bit), then `y' is in the range */ /* */ /* -2^n..2^n-1 */ /* */ /* We want to shift `a', `b', and `c' concurrently in order */ /* to ensure that they all fit in 8.16 values, which maps */ /* to the integer range `-2^23..2^23-1'. */ /* */ /* Necessarily, we need to shift `a', `b', and `c' so that */ /* the most significant bit of its absolute values is at */ /* _most_ at position 23. */ /* */ /* We begin by computing `t1' as the bitwise `OR' of the */ /* absolute values of `a', `b', `c'. */ t1 = (FT_ULong)( ( a >= 0 ) ? a : -a ); t2 = (FT_ULong)( ( b >= 0 ) ? b : -b ); t1 |= t2; t2 = (FT_ULong)( ( c >= 0 ) ? c : -c ); t1 |= t2; /* Now we can be sure that the most significant bit of `t1' */ /* is the most significant bit of either `a', `b', or `c', */ /* depending on the greatest integer range of the particular */ /* variable. */ /* */ /* Next, we compute the `shift', by shifting `t1' as many */ /* times as necessary to move its MSB to position 23. This */ /* corresponds to a value of `t1' that is in the range */ /* 0x40_0000..0x7F_FFFF. */ /* */ /* Finally, we shift `a', `b', and `c' by the same amount. */ /* This ensures that all values are now in the range */ /* -2^23..2^23, i.e., they are now expressed as 8.16 */ /* fixed-float numbers. This also means that we are using */ /* 24 bits of precision to compute the zeros, independently */ /* of the range of the original polynomial coefficients. */ /* */ /* This algorithm should ensure reasonably accurate values */ /* for the zeros. Note that they are only expressed with */ /* 16 bits when computing the extrema (the zeros need to */ /* be in 0..1 exclusive to be considered part of the arc). */ if ( t1 == 0 ) /* all coefficients are 0! */ return; if ( t1 > 0x7FFFFFUL ) { do { shift++; t1 >>= 1; } while ( t1 > 0x7FFFFFUL ); /* this loses some bits of precision, but we use 24 of them */ /* for the computation anyway */ a >>= shift; b >>= shift; c >>= shift; } else if ( t1 < 0x400000UL ) { do { shift++; t1 <<= 1; } while ( t1 < 0x400000UL ); a <<= shift; b <<= shift; c <<= shift; } } /* handle a == 0 */ if ( a == 0 ) { if ( b != 0 ) { t = - FT_DivFix( c, b ) / 2; test_cubic_extrema( y1, y2, y3, y4, t, min, max ); } } else { /* solve the equation now */ d = FT_MulFix( b, b ) - FT_MulFix( a, c ); if ( d < 0 ) return; if ( d == 0 ) { /* there is a single split point at -b/a */ t = - FT_DivFix( b, a ); test_cubic_extrema( y1, y2, y3, y4, t, min, max ); } else { /* there are two solutions; we need to filter them */ d = FT_SqrtFixed( (FT_Int32)d ); t = - FT_DivFix( b - d, a ); test_cubic_extrema( y1, y2, y3, y4, t, min, max ); t = - FT_DivFix( b + d, a ); test_cubic_extrema( y1, y2, y3, y4, t, min, max ); } } } }#endif /*************************************************************************/ /* */ /* <Function> */ /* BBox_Cubic_To */ /* */ /* <Description> */ /* This function is used as a `cubic_to' emitter during */ /* FT_Raster_Decompose(). It checks a cubic Bezier curve with the */ /* current bounding box, and computes its extrema if necessary to */ /* update it. */ /* */ /* <Input> */ /* control1 :: A pointer to the first control point. */ /* */ /* control2 :: A pointer to the second control point. */ /* */ /* to :: A pointer to the destination vector. */ /* */ /* <InOut> */ /* user :: The address of the current walk context. */ /* */ /* <Return> */ /* Always 0. Needed for the interface only. */ /* */ /* <Note> */ /* In the case of a non-monotonous arc, we don't compute directly */ /* extremum coordinates, we subdivide instead. */ /* */ static int BBox_Cubic_To( FT_Vector* control1, FT_Vector* control2, FT_Vector* to, TBBox_Rec* user ) { /* we don't need to check `to' since it is always an `on' point, thus */ /* within the bbox */ if ( CHECK_X( control1, user->bbox ) || CHECK_X( control2, user->bbox ) ) BBox_Cubic_Check( user->last.x, control1->x, control2->x, to->x, &user->bbox.xMin, &user->bbox.xMax ); if ( CHECK_Y( control1, user->bbox ) || CHECK_Y( control2, user->bbox ) ) BBox_Cubic_Check( user->last.y, control1->y, control2->y, to->y, &user->bbox.yMin, &user->bbox.yMax ); user->last = *to; return 0; } /* documentation is in ftbbox.h */ FT_EXPORT_DEF( FT_Error ) FT_Outline_Get_BBox( FT_Outline* outline, FT_BBox *abbox ) { FT_BBox cbox; FT_BBox bbox; FT_Vector* vec; FT_UShort n; if ( !abbox ) return FT_Err_Invalid_Argument; if ( !outline ) return FT_Err_Invalid_Outline; /* if outline is empty, return (0,0,0,0) */ if ( outline->n_points == 0 || outline->n_contours <= 0 ) { abbox->xMin = abbox->xMax = 0; abbox->yMin = abbox->yMax = 0; return 0; } /* We compute the control box as well as the bounding box of */ /* all `on' points in the outline. Then, if the two boxes */ /* coincide, we exit immediately. */ vec = outline->points; bbox.xMin = bbox.xMax = cbox.xMin = cbox.xMax = vec->x; bbox.yMin = bbox.yMax = cbox.yMin = cbox.yMax = vec->y; vec++; for ( n = 1; n < outline->n_points; n++ ) { FT_Pos x = vec->x; FT_Pos y = vec->y; /* update control box */ if ( x < cbox.xMin ) cbox.xMin = x; if ( x > cbox.xMax ) cbox.xMax = x; if ( y < cbox.yMin ) cbox.yMin = y; if ( y > cbox.yMax ) cbox.yMax = y; if ( FT_CURVE_TAG( outline->tags[n] ) == FT_CURVE_TAG_ON ) { /* update bbox for `on' points only */ if ( x < bbox.xMin ) bbox.xMin = x; if ( x > bbox.xMax ) bbox.xMax = x; if ( y < bbox.yMin ) bbox.yMin = y; if ( y > bbox.yMax ) bbox.yMax = y; } vec++; } /* test two boxes for equality */ if ( cbox.xMin < bbox.xMin || cbox.xMax > bbox.xMax || cbox.yMin < bbox.yMin || cbox.yMax > bbox.yMax ) { /* the two boxes are different, now walk over the outline to */ /* get the Bezier arc extrema. */ static const FT_Outline_Funcs bbox_interface = { (FT_Outline_MoveTo_Func) BBox_Move_To, (FT_Outline_LineTo_Func) BBox_Move_To, (FT_Outline_ConicTo_Func)BBox_Conic_To, (FT_Outline_CubicTo_Func)BBox_Cubic_To, 0, 0 }; FT_Error error; TBBox_Rec user; user.bbox = bbox; error = FT_Outline_Decompose( outline, &bbox_interface, &user ); if ( error ) return error; *abbox = user.bbox; } else *abbox = bbox; return FT_Err_Ok; }/* END */
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