npqs0.c
来自「数值分析算法描述与习题解答」· C语言 代码 · 共 18 行
C
18 行
#include "stdio.h"
#include "npqs.c"
main()
{ double t,z;
static double x[10]={-1.0,-0.8,-0.65,-0.4,-0.3,
0.0,0.2,0.45,0.8,1.0};
static double y[10]={0.0384615,0.0588236,0.0864865,0.2,0.307692,
1.0,0.5,0.164948,0.0588236,0.0384615};
printf("\n");
t=-0.85; z=npqs(x,y,10,t);
printf("t=%6.3f, z=%e\n",t,z);
t=0.25; z=npqs(x,y,10,t);
printf("t=%6.3f, z=%e\n",t,z);
printf("\n");
}
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?