eatk0.c

来自「数值分析算法描述与习题解答」· C语言 代码 · 共 17 行

  #include "stdio.h"
  #include "eatk.c"
  main()
  { double t,z,x0,h,eps;
    static double y[10]={0.904837,0.818731,0.740818,0.670320,
       0.606531,0.548812,0.496585,0.449329,0.406570,0.367879};
    eps=1.0e-6; x0=0.1; h=0.1;
    printf("\n");
    t=0.15; z=eatk(x0,h,10,y,t,eps);
    printf("t=%6.3f,   z=%e\n",t,z);
    t=0.55; z=eatk(x0,h,10,y,t,eps);
    printf("t=%6.3f,   z=%e\n",t,z);
    printf("\n");
  }