elgr0.c
来自「数值分析算法描述与习题解答」· C语言 代码 · 共 19 行
C
19 行
#include "stdio.h"
#include "elgr.c"
main()
{ double x0,h,t,z;
static double y[10]={0.904837,0.818731,0.740818,0.670320,0.606531,
0.548812,0.496585,0.449329,0.406570,0.367879};
x0=0.1; h=0.1;
printf("\n");
t=0.25; z=elgr(x0,h,10,y,t);
printf("t=%6.3f, z=%e\n",t,z);
t=0.63; z=elgr(x0,h,10,y,t);
printf("t=%6.3f, z=%e\n",t,z);
t=0.95; z=elgr(x0,h,10,y,t);
printf("t=%6.3f, z=%e\n",t,z);
printf("\n");
}
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