📄 lubksub2.m
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function x = lubksub2(lu,indx,b)% Solve Ax = b, where A has been factored into (lu,indx) using lu2% Todd K. Moon% Copyright 2004 by Todd K. Moon% Permission is granted to use this program/data% for educational/research only[m,n] = size(lu);if(m < n) error('Matrix should be square or tall');endb = b(:);b = b(indx);% Do the backsubstitution to solve Ly = Pb, where P is determined by indxx = zeros(n,1);for i=1:n sum = b(i); j = 1:i-1; sum = sum - lu(i,j)*b(j); b(i) = mod(sum,2);end% Solve Ux = yfor i=n:-1:1 sum = b(i); j = i+1:n; sum = sum - lu(i,j)*x(j); x(i) = mod(sum,2);end
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