modelandviewdefiningexception.java

一个关于Spring框架的示例应用程序,简单使用,可以参考.

/*
 * Copyright 2002-2004 the original author or authors.
 * 
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 * 
 *      http://www.apache.org/licenses/LICENSE-2.0
 * 
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */ 

package org.springframework.web.servlet;

import javax.servlet.ServletException;

import org.springframework.web.servlet.ModelAndView;

/**
 * Exception to be thrown on error conditions that should forward
 * to a specific view with a specific model.
 *
 * <p>Can be thrown at any time during handler processing.
 * This includes any template methods of pre-built controllers.
 * For example, a form controller might abort to a specific error page
 * if certain parameters do not allow to proceed with the normal workflow.
 *
 * @author Juergen Hoeller
 * @since 22.11.2003
 */
public class ModelAndViewDefiningException extends ServletException {

	private ModelAndView modelAndView;

	/**
	 * Create new ModelAndViewDefiningException with the given ModelAndView,
	 * typically representing a specific error page.
	 * @param modelAndView ModelAndView with view to forward to and model to expose
	 */
	public ModelAndViewDefiningException(ModelAndView modelAndView) {
		if (modelAndView == null) {
			throw new IllegalArgumentException("modelAndView must not be null in ModelAndViewDefiningException");
		}
		this.modelAndView = modelAndView;
	}

	/**
	 * Return the ModelAndView that this exception contains for forwarding to.
	 */
	public ModelAndView getModelAndView() {
		return modelAndView;
	}

}