📄 text7-41.htm
字号:
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
</head>
<body bgcolor="#FFFFFF" link="#0000FF" vlink="#3399FF" alink="#FF0066">
<div id="Layer1" style="position:absolute; width:711px; height:21px; z-index:1; top: 10px; background-color: #CCCCCC; layer-background-color: #CCCCCC; border: 1px none #000000; left: 26px"><b>|</b><font face="宋体" size="2"><a href="../text1/text1-0.htm">第一章</a></font><b>|</b><font face="宋体" size="2"><a href="../text2/text2-0.htm">第二章</a></font><b>|</b><font face="宋体" size="2"><a href="../text3/text3-0.htm">第三章</a></font><b>|</b><font face="宋体" size="2"><a href="../text4/text4-0.htm">第四章</a></font><b>|</b><font face="宋体" size="2"><a href="../text5/text5-0.htm">第五章</a></font><b>|</b><font face="宋体" size="2"><a href="../text6/text6-0.htm">第六章</a></font><b>|</b><font face="宋体" size="2">第七章</font><b>|</b><font face="宋体" size="2"><a href="../text8/text8-0.htm">第八章</a></font><b>|</b><font face="宋体" size="2"><a href="../text9/text9-0.htm">第九章</a></font><b>|</b><font face="宋体" size="2"><a href="../text10/text10-0.htm">第十章</a></font><b>|</b><font size="2" face="宋体"><a href="../textA/textA-0.htm">算法分析</a><b><font color="#000000">|</font></b>
</font></div>
<pre align="left">
<b><font face="Arial, Helvetica, sans-serif" size="4" color="#FF0000"><i>n</i></font><font face="Arial, Helvetica, sans-serif" size="4" color="#000000"> records --> <i><font color="#FF0000"> m </font></i> runs --> [ <img src="image/log2m.gif" width="68" height="24" align="middle"> ] + 1 level --> k-way merge
--> merge [ <img src="image/logkm.gif" width="69" height="24" align="middle"> ] passes
merge k-runs ( <font color="#0033CC"><i>s<font size="2">1</font>,s<font size="2">2</font>,s<font size="2">3</font>,, …,sk<font size="2"> </font></i></font> ) --> O((<i>k-1) </i> <img src="image/sums.gif" width="46" height="29" align="middle">) =n(k-1) computing time
<font color="#FF0000">total computing time : </font><i>n(k-1)</i> <img src="image/logkm.gif" width="69" height="24" align="middle"> computing number
<i>n(k-1)</i> <img src="image/logkm.gif" width="69" height="24" align="middle"> = <i> n(k-1)</i> <img src="image/log2m.gif" width="68" height="24" align="middle"> / <img src="image/log2k.gif" width="61" height="24" align="middle"> = <i>n</i> <img src="image/log2m.gif" width="68" height="24" align="middle"> * <i>(k-1) / </i> <img src="image/log2k.gif" width="61" height="24" align="middle">
<i><font color="#FF0000">As k increase , the reduction in input/output time will be offset
by the resulting increase in CPU time needed to perform the
k-way merge. </font></i>
<font color="#0033CC">the total internal processing time per level</font> = <font color="#FF0000">O(n</font><img src="image/log2k.gif" width="61" height="24" align="middle"><font color="#FF0000"> )</font>
<font color="#0033CC">the total internal processing time :</font>
<font color="#FF0000"> O( <i>n </i></font><img src="image/log2k.gif" width="61" height="24" align="middle"> <font color="#FF0000"> </font><img src="image/logkm.gif" width="69" height="24" align="middle"><font color="#FF0000"> ) = O (<i> n</i> </font><img src="image/log2m.gif" width="68" height="24" align="middle"><font color="#FF0000"> )</font></font></b></pre>
<p> </p>
<table width="731" cellspacing="0" cellpadding="0">
<tr>
<td width="327"> </td>
<td width="271"><a href="../index.htm"><img width="60" height="25" usemap="#MapMap4" border="0" src="../../images/home.gif"></a><a href="../index.htm"><map name="MapMap4"><area shape="rect" coords="42,-34,88,-15" href="text0.htm"><area shape="rect" coords="4,4,55,23" href="text7-index.htm"></map></a></td>
<td width="131"><font face="楷体_GB2312" size="2"><b><a href="text7-40.htm">上一页</a>
<a href="text7-42.htm">下一页</a></b></font></td>
</tr>
</table>
<p> </p>
</body>
</html>
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -