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<b><font face="Arial, Helvetica, sans-serif" size="4" color="#0033CC">program </font><font face="Arial, Helvetica, sans-serif" size="4" color="#000000"> <font color="#FF0000">quicksort</font> ( list, 0, n-1 )
void<font color="#FF0000"> quicksort</font> (element list[ ], int left, int right)
<i><font size="3" color="#CC0099">/* sort list[left],...,list[right] into nondecreasing order on the key
field,list[left].key is arbitrarily chosen as the pivot key,it is assumed
that list[left].key <= list[right+1].key. */</font></i>
{ int pivot, i, j;
element temp;
if (left < right){ <font size="3" color="#FF0033">left <font color="#000000">|______________|</font> right</font>
i = left; j = right + 1; <font size="2"><i><font color="#FF0033"> i -></font></i></font> <font size="2" color="#FF0033"><i> <- j</i></font>
pivot = list [left].key;
do{ <i><font size="3" color="#CC0099">/* search for keys from the left and right sublists,
swapping out-of-order elements until the left and
right boundaries cross or meet */</font></i>
do i++; while (list[ i ].key < pivot);
do j--; while (list[ j ], key > pivot);
if (i < j)
SWAP(list [ i ], list [ j ], temp);
} while ( i < j);
SWAP(list [ left ], list[ j ], temp);
<font color="#FF0000">quicksort</font>( list, left, j-1);
<font color="#FF0000">quicksort</font>( list, j+1, right);
}
}
</font></b></pre>
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