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<b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000">(2) <font color="#FF0000">Iterative merge sort </font> O( <img src="image/nlogn.gif" width="79" height="24" align="middle"> )
void <font color="#FF0000">merge_pass</font>(element list[ ],element sorted[ ],int n,int length)
{ <i><font size="3" color="#CC0099">/* perform one pass of the merge sort.It merges adjacent pairsof subfiles
from list into sorted. n is the number of element in the list.length is the length
of the subfile */
</font></i> int i, j;
for (i = 0; i <= n-2 * length; i += 2 * length)
<font color="#FF0000"> merge</font>(list, sorted, i, i + length - 1, i + 2 * length -1);
if( i+length < n)
<font color="#FF0000">merge</font>(list, sorted, i, i+length-1, n-1);
else </font></b></pre>
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<pre><b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000"> for (j = i; j < n; j++)
sorted[ j ] = list[ j ];
}</font></b></pre>
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<pre><img src="image/merge3.gif" width="344" height="90"></pre>
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<pre><b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000">void <font color="#FF0000">merge_sort</font>(element list[ ], int n)
<i><font size="3" color="#CC0099">/* perform a merge sort on the files */</font></i>
{ int length = 1;
<i><font size="3" color="#CC0099">/* current length being merged */</font></i>
element extra[MAX_SIZE];
while(length < n){
<font color="#FF0000">merge_pass</font>(list, extra, n, length);
length *= 2;
<font color="#FF0000">merge_pass</font>(extra, list, n, length);
length *= 2;
}
} </font></b></pre>
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<pre><img src="image/merge2.gif" width="326" height="162"></pre>
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