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<pre align="left"><font face="Arial, Helvetica, sans-serif" size="4" color="#000000"><b>
(3) <font color="#FF0000"> List verification</font>
<font color="#0033CC">compare lists</font> to verify that they are identical, or to identify the
discrepancies. ( an instance of repeatedly searching one list ,
using each key in the other list as the search key )
<font color="#FF0000">three types of error</font>
1. a record with key list1 [i ].key appears in the first list, but there
is no record with the same key in the second list (list2).
2. a record with key list2 [i ].key appears in the second list, but
there is no record with the same key in the first list (list1).
3. list1[ i ].key = list2 [ i ].key, but the two records do not match on
at least one of the other fields.
<font color="#FF0000">program1 </font> <font color="#FF0000">O( mn )</font>
void<font color="#FF0000"> verify1</font>(element list1[ ], element list2[ ], int n, int m)
<i><font size="3" color="#CC0099">/* compare two unordered lists list1 and list2 */</font></i>
{ int i, j;
int marked[MAX_SIZE];
for (i = 0; i < m; i++)
marked[i] = FALSE;
for (i = 0; i < n; i++)
if ((j = seqsearch(list2, m, list1[ i ].key)) < 0)
printf("%d is not in list2 \n", list1[ i ].key);
else
<i><font size="3" color="#CC0099"> /* check each of the other fields from list1[i] and
list2[j],and print out any discrepancies */</font></i>
marked[j] = TRUE;
for (i = 0; i < m; i++)
if ( !marked[ i ])
printf("%d is not in list1\n", list2[ i ].key);</b></font>
<b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000">}
</font></b></pre>
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