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<b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000">typedef struct {
int key;
int link;
int linkb; <i><font size="3" color="#CC0099"> /* back link */</font></i>
} <font color="#FF0000">element</font>:
void <font color="#FF0000">list_sort1</font>(element list[ ],int n,int start)
<i><font size="3" color="#CC0099">/* start is a pointer to the list of n sorted elements,linked together by the field
link,linkb is assumed to be present in each element.the elements are rearranged
so that the resulting elements list[0],...,list[n-1] are consecutive and sorted */
</font></i><font size="3" color="#CC0099"><font size="4" color="#000000">{</font></font></font></b></pre>
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<pre><b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000"> int i, last, current;
element temp;
last = -1; </font></b></pre>
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<pre align="left"><b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000"> for (current = start; current != -1; current = list[current].link)
{<i><font size="3" color="#CC0099">/* establish the back links for the list */</font></i>
list[current].linkb = last;
last = current;
}
for (i = 0; i < n-1; i++){
<i><font size="3" color="#CC0099"> /*move list[start] to position i while maintaining the list */</font></i> </font></b></pre>
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<pre><b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000"> if (start != i){
if (list [ i ].link+1)
<font color="#FF0033"><i>1</i></font> list [list [ i ].link].linkb = start; <font color="#FF0033"></font>
<font color="#FF0033"><i>2</i></font> list [ list[ i ].linkb].link = start;
SWAP ( list[start], list[i], temp);
}
start = list[i].link;
}
}</font></b></pre>
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<pre align="left"><b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000"><font color="#0033CC">complexity</font> <i><font size="3" color="#CC0099">O( mn )</font></i>
<font color="#FF0000"> n</font> --- the number of records in the list
<font color="#FF0000"> m</font> --- each record is m words long
</font></b></pre>
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