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<div id="Layer1" style="position:absolute; width:711px; height:21px; z-index:1; top: 10px; background-color: #CCCCCC; layer-background-color: #CCCCCC; border: 1px none #000000; left: 26px"><b>|</b><font face="宋体" size="2"><a href="../text1/text1-0.htm">第一章</a></font><b>|</b><font face="宋体" size="2"><a href="../text2/text2-0.htm">第二章</a></font><b>|</b><font face="宋体" size="2">第三章</font><b>|</b><font face="宋体" size="2"><a href="../text4/text4-0.htm">第四章</a></font><b>|</b><font face="宋体" size="2"><a href="../text5/text5-0.htm">第五章</a></font><b>|</b><font face="宋体" size="2"><a href="../text6/text6-0.htm">第六章</a></font><b>|</b><font face="宋体" size="2"><a href="../text7/text7-0.htm">第七章</a></font><b>|</b><font face="宋体" size="2"><a href="../text8/text8-0.htm">第八章</a></font><b>|</b><font face="宋体" size="2"><a href="../text9/text9-0.htm">第九章</a></font><b>|</b><font face="宋体" size="2"><a href="../text10/text10-0.htm">第十章</a></font><b>|</b><font size="2" face="宋体"><a href="../textA/textA-0.htm">算法分析</a><b><font color="#000000">|</font></b>
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<pre align="left"><b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000">
</font><font face="Arial, Helvetica, sans-serif" size="5" color="#FF0033"><b>!Configuration when stack i meet stack i =1,
but the memory is not full
</b></font><img src="image/mulstack1.gif" width="569" height="97" hspace="100"><b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000"><i><font color="#0033CC"> b=boundary ,t=top</font></i></font></b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000">
<font color="#FF0033">We can design stack_full so that we can add elements to this
stack untill the array is full in the following way:</font>
(i) create a space between stack <i>stack_no</i> and <i>stack_no+1.</i>
determine the least j (<i> stack_no < j < n</i> )such that there is free
space between stack j and j + 1 (<i> top [j ] < boundary[ j + 1 ] </i>).
If there is such a j , then move <i>stack_no +1</i>, <i>stack_no +2</i>,…, <i>j</i>
one position to right.
(ii)create a space between stack<i> stack_no </i>and <i>stack_no+1</i>.
look to the left of <i>stack_no</i>, Find the largest j such that
<i>0 <= j < stack_no </i>and there is space between j and j +1
(<i>top [j] < boundary [j + 1]</i>). If there is such a j , move stacks
<i> j, j+1,,……, stack_no o</i>ne space to left.
(iii) If there is no j satisfying either condition (i) or (ii). then all
<font size="3">MEMORY_SIZE</font> spaces of memory are utilized and there is
no free space. In this case stack_full determinate with an
error message.
<font color="#FF0000">Exercises <font color="#000000">page 133/ 2
</font></font></font></b></pre>
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