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<b><font face="Arial, Helvetica, sans-serif" size="4" color="#000000">〖<font color="#FF0000">example</font>〗
operation sequence:<i><font color="#0033CC"> I1, I2, D1, I3, I4, I5, I6, D2, I7</font></i>
actual cost: <i> I1 ~ I7 -- 1, D1 - 8, D2 -- 10</i> ( unit of time )
total cost = 25
if 2 units <i>(D1) --> I1, I2, </i> 4 units <i>( D2) --> I2 ~ I6</i>
the amortized cost of each of <i>I1 ~ I6</i> = 2 units
the amortized cost of each of <i>D1 ~ C2</i> = 6 units
the total amortized cost = (2*6+1*+2*6 ) = 25 units
for any sequence of insert and delete min operations:
<font color="#0033CC">actual sequence cost </font>= i + 10 * d
<font color="#0033CC">amortized sequence cost</font> = 2 * i + 6 * d
bound on the sequence cost = min {2 * i + 6 * d, i + 10 * d}
while individual delete operations on an binomial heap may be
expensive, the cost of any sequence of binomial heap operations
is actually quite small
</font></b></pre>
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