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<pre align="left"><b><font face="宋体" size="4" color="#000000">
<font color="#FF0033">例6<font face="Arial, Helvetica, sans-serif">.</font>1</font> 组件布局问题
<img src="IMAGE/text10-j0.gif" width="437" height="170">
<font color="#FF0033">问题:</font>如何安排a,b,c,d,e插件,使导线总长度最短。
<font color="#FF0033">原始成本</font>:cost=<font color="#FF0000">97</font>
相邻插件的距离为1单位、线上标记为连接条数
<font size="3">a-> 3*1+4*2+2*3+7*4=45
b-> 4*1+6*2+3*3 =25
c-> 5*1+8*2 =21
d-> 6*1 =06</font>
<font color="#FF0033">局部变换:</font>
1.<font color="#0033CC">变换2相邻组件Pi和Pj.</font>
<i><font face="Arial, Helvetica, sans-serif"> L(j) = ∑ W(PK , Pj ) (1 ≤ k ≤ j-1)
R(j) = ∑ W(PK , Pj ) (j+1 ≤ k ≤ n)
</font></i>
长度变化 = <i><font face="Arial, Helvetica, sans-serif">L(i) - R(i) + R(i+1) - L(i+1) + 2W(Pi, Pi+1)
</font></i><img src="IMAGE/text10-k.gif" width="424" height="184">
如长度变换<0,则交换i和j后,解得到改进。
2.<font color="#0033CC">对某个i和j,把组件i插到Pj和Pj+1之间。</font>
3.<font color="#0033CC">交换任意二组件Pi和Pj.</font>
(a) 原cost=<font color="#FF0000">97</font>
(b) 如d, e交换
L(d) 即a, b, c到d长度 <i><font face="Arial, Helvetica, sans-serif">= 2+6+5 = 13</font></i>
R(d) 即e 到 d 长度<i><font face="Arial, Helvetica, sans-serif"> <font color="#FF0000">= 6</font></font></i>
L(e) 即a, b, c, d到e长度<i><font face="Arial, Helvetica, sans-serif"> = 7+3+8+6 = 24</font></i>
R(e) 无后结点 <i><font face="Arial, Helvetica, sans-serif">= 0</font></i>
<font color="#FF0033">长度变化=</font>
<i><font face="Arial, Helvetica, sans-serif"> L(d) - R(d) + R(e) - L(e) + 2w(d,e) = 13 - 6 + 0 - 24 + 2×6 = -5 < 0</font></i>
<font color="#FF0033">cost =92</font>
(c)<font color="#0033CC"> 如c, e交换</font>
<font color="#FF0033">cost=91</font>,相对(a)的局部最优解,不是全局最优。
(d)<font color="#0033CC"> 最优解</font> (a, c, e, d, b)
<font color="#FF0033">cost=84 </font> <font color="#FF0033">为最优解。</font>
</font></b></pre>
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