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来自「浙江大学计算机学院数据结构课程的教学课件」· HTM 代码 · 共 61 行
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<b>|</b><font face="宋体" size="2">第一章</font><b>|</b><font face="宋体" size="2"><a href="text2-0.htm">第二章</a></font><b>|</b><font face="宋体" size="2"><a href="text3-0.htm">第三章</a></font><b>|</b><font face="宋体" size="2"><a href="text4-0.htm">第四章</a></font><b>|</b><font face="宋体" size="2"><a href="text5-0.htm">第五章</a></font><b>|</b><font face="宋体" size="2"><a href="text6-0.htm">第六章</a></font><b>|</b><font face="宋体" size="2"><a href="text7-0.htm">第七章</a></font><b>|</b><font face="宋体" size="2"><a href="text8-0.htm">第八章</a></font><b>|</b><font face="宋体" size="2"><a href="text9-0.htm">第九章</a></font><b>|</b><font face="宋体" size="2"><a href="text10-0.htm">第十章</a></font><b>|</b><font size="2" face="宋体"><a href="textA-0.htm">算法分析</a><b><font color="#000000">|</font></b>
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<b>|</b><font face="宋体" size="2">第一章</font><b>|</b><font face="宋体" size="2"><a href="../text2/text2-0.htm">第二章</a></font><b>|</b><font face="宋体" size="2"><a href="../text3/text3-0.htm">第三章</a></font><b>|</b><font face="宋体" size="2"><a href="../text4/text4-0.htm">第四章</a></font><b>|</b><font face="宋体" size="2"><a href="../text5/text5-0.htm">第五章</a></font><b>|</b><font face="宋体" size="2"><a href="../text6/text6-0.htm">第六章</a></font><b>|</b><font face="宋体" size="2"><a href="../text7/text7-0.htm">第七章</a></font><b>|</b><font face="宋体" size="2"><a href="../text8/text8-0.htm">第八章</a></font><b>|</b><font face="宋体" size="2"><a href="../text9/text9-0.htm">第九章</a></font><b>|</b><font face="宋体" size="2"><a href="../text10/text10-0.htm">第十章</a></font><b>|</b><font size="2" face="宋体"><a href="../textA/textA-0.htm">算法分析</a><b><font color="#000000">|</font></b>
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<pre><font face="Arial, Helvetica, sans-serif" size="4"><b>
〖example 4〗<font color="#FF0033">permutation</font><br>
(a,b,c ) -------> {(a,b,c),(a,c,b),(b,a,c),(b,c,a),(c,a,b),(c,b,a)}
( a,b,c,d ) -------> a+ all permutation of (b,c,d)
b+ all permutation of (a,c,d) --> 4·6 permutations
c+ all permutation of (b,a,d)
d+ all permutation of (b,c,a)
void <font color="#ff0033">perm</font> ( char *list , int i, int n ) <i><font size="3" color="#CC0099"> /*调用时 i = 0, n=4*/</font></i>
{ <i><font size="3" color="#CC0099"> /* generate all the permutations of list [ i ] to list [ n ] */</font></i>
int j , temp;
if ( i == n ) { <i><font size="3" color="#CC0099"> /* i = n 说明所有交换已完成，为递归逸出口*/ </font></i>
for ( j = 0; j <= n; j++ )
printf ( "%c ", list [ j ] );
printf ( " " );
}
else { <i><font size="3" color="#CC0099">/* list [i ] to list [n ] has more than one permutation,
generate these recursively*/</font></i> </b></font></pre>
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<pre><font face="Arial, Helvetica, sans-serif" size="4"><b> for ( j = i; j <= n; j++) {
swap( list [i ], list [ j ], temp);
<font color="#ff0033">perm</font>( list, i + 1, n);
swap(list [ i ], list [j ], temp);</b></font></pre>
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<pre><font face="Arial, Helvetica, sans-serif" size="4"><b> }
}
}
</b></font><font face="Arial, Helvetica, sans-serif" color="#000000" size="4"><b> <font color="#FF0033"> Exercises </font> P<font size="3">12</font>---<font color="#FF0033">2,12 </font>
</b></font></pre>
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