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来自「浙江大学计算机学院数据结构课程的教学课件」· HTM 代码 · 共 55 行
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<pre align="left"><b><font face="Arial" size="4">
<font color="#0033CC">Algorithm</font><font color="#FF0033"> </font><i><font color="#FF0033">( O(strlen(string) + strlen( pat )) )</font></i>
<br><font color="#FF0033">example:</font>
s = <i>s0 s1 … sm-1</i>
pat =<i> ' a b c a b c a c a b '
</i>
s = <i> ' - a b ? ? ? . . . . ? '</i>
pat = <i> ' a b c a b c a c a b ' <font face="Arial, Helvetica, sans-serif" size="3" color="#CC0099">/* si+2<>c, next </font></i><font face="Arial, Helvetica, sans-serif" size="3" color="#CC0099"><i>si+2~p1 */</i></font><i>
</i>
s = <i> ' - a b c a ? ? . . . ? '</i>
pat = <i> ' a b c a b c a c a b ' <font face="Arial, Helvetica, sans-serif" size="3" color="#CC0099">/* si+4<>b, next </font></i><font face="Arial, Helvetica, sans-serif" size="3" color="#CC0099"><i>si+4~p2 */</i></font><i></i><i>
</i>
【<font color="#0033CC">definition</font>】
if p =<i>p0p1p…pn-1 </i>is a pattern, then its failure function<i>, p, i</i><i>s</i>
defined as:</font></b></pre>
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<td rowspan="2" width="10%"><b><font face="Arial" size="4"><i> f(j ) = </i></font></b></td>
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<pre><b><font face="Arial" size="4"> <i> largest</i><i> i < j </i><font size="3" color="#FF0099">such that <i> p0p1… pi = pj-i p j-i+<font color="#000000">1</font>…pj
</i></font> <font size="3" color="#FF0099">if such an i >= 0 exists</font><font size="3">.</font></font></b></pre>
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<pre><b><font face="Arial" size="4"> - 1 <font size="3" color="#FF0099"> otherwise</font></font></b></pre>
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<pre align="left"><b><font face="Arial" size="4"> <i> <font color="#FF0033">j </font> 0 1 2 3 4 5 6 7 8 9
<font color="#FF0033"> pat </font> a b c a b c a c a b
<font color="#FF0033"> f </font> <font color="#0033CC">-1 -1 -1 0 1 2 3 -1 0 1</font></i>
<i>
</i></font></b></pre>
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