c45347d.ada

来自「linux下编程用 编译软件」· ADA 代码 · 共 94 行

ADA
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-- C45347D.ADA--                             Grant of Unlimited Rights----     Under contracts F33600-87-D-0337, F33600-84-D-0280, MDA903-79-C-0687,--     F08630-91-C-0015, and DCA100-97-D-0025, the U.S. Government obtained --     unlimited rights in the software and documentation contained herein.--     Unlimited rights are defined in DFAR 252.227-7013(a)(19).  By making --     this public release, the Government intends to confer upon all --     recipients unlimited rights  equal to those held by the Government.  --     These rights include rights to use, duplicate, release or disclose the --     released technical data and computer software in whole or in part, in --     any manner and for any purpose whatsoever, and to have or permit others --     to do so.----                                    DISCLAIMER----     ALL MATERIALS OR INFORMATION HEREIN RELEASED, MADE AVAILABLE OR--     DISCLOSED ARE AS IS.  THE GOVERNMENT MAKES NO EXPRESS OR IMPLIED --     WARRANTY AS TO ANY MATTER WHATSOEVER, INCLUDING THE CONDITIONS OF THE--     SOFTWARE, DOCUMENTATION OR OTHER INFORMATION RELEASED, MADE AVAILABLE --     OR DISCLOSED, OR THE OWNERSHIP, MERCHANTABILITY, OR FITNESS FOR A--     PARTICULAR PURPOSE OF SAID MATERIAL.--*-- CHECK THAT CATENATION IS DEFINED FOR ACCESS TYPES AS COMPONENT TYPES.-- JWC 11/15/85WITH REPORT; USE REPORT;PROCEDURE C45347D ISBEGIN     TEST ("C45347D", "CHECK THAT CATENATION IS DEFINED " &                      "FOR ACCESS TYPES AS COMPONENT TYPES");     DECLARE          SUBTYPE INT IS INTEGER RANGE 1 .. 4;          TYPE ACC IS ACCESS INT;          TYPE A IS ARRAY ( INT RANGE <>) OF ACC;          AC1 : ACC := NEW INT'(1);          AC2 : ACC := NEW INT'(2);          AC3 : ACC := NEW INT'(3);          AC4 : ACC := NEW INT'(4);          A1 : A(1 .. 2) := (AC1, AC2);          A2 : A(1 .. 2) := (AC3, AC4);          A3 : A(1 .. 4) := (AC1, AC2, AC3, AC4);          A4 : A(1 .. 4);          A5 : A(1 .. 4) := (AC4, AC3, AC2, AC1);     BEGIN          A4 := A1 & A2;          IF A3 /= A4 THEN               FAILED ("INCORRECT CATENATION FOR TWO ARRAYS OF ACCESS");          END IF;          A4 := A5;          A4 := A1 & A2(1) & AC4;          IF A3 /= A4 THEN               FAILED ("INCORRECT CATENATION FOR ARRAY OF ACCESS, " &                       "AND ACCESS");          END IF;          A4 := A5;          A4 := AC1 & (A1(2) & A2);          IF A3 /= A4 THEN               FAILED ("INCORRECT CATENATION FOR ACCESS, AND ARRAY " &                       "OF ACCESS");          END IF;          A4 := A5;          A4 := AC1 & A1(2) & (A2(1) & AC4);          IF A3 /= A4 THEN               FAILED ("INCORRECT CATENATION FOR ACCESS");          END IF;     END;     RESULT;END C45347D;

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