strcpy.c

来自「c21Examples.rar」· C语言 代码 · 共 34 行

/* Demonstrates strcpy(). */
#include <stdlib.h>
#include <stdio.h>
#include <string.h>

char source[] = "The source string.";

int main( void )
{
    char dest1[80];
    char *dest2, *dest3;

    printf("\nsource: %s", source );

    /* Copy to dest1 is okay because dest1 points to */
    /* 80 bytes of allocated space. */

    strcpy(dest1, source);
    printf("\ndest1:  %s", dest1);

    /* To copy to dest2 you must allocate space. */

    dest2 = (char *)malloc(strlen(source) +1);
    strcpy(dest2, source);
    printf("\ndest2:  %s\n", dest2);

    /* Copying without allocating destination space is a no-no. */
    /* The following could cause serious problems. */

    /* strcpy(dest3, source); */
    return 0;
}