strncpy.c
来自「c21Examples.rar」· C语言 代码 · 共 30 行
C
30 行
/* Using the strncpy() function. */
#include <stdio.h>
#include <string.h>
char dest[] = "..........................";
char source[] = "abcdefghijklmnopqrstuvwxyz";
int main( void )
{
size_t n;
while (1)
{
puts("Enter the number of characters to copy (1-26)");
scanf("%d", &n);
if (n > 0 && n< 27)
break;
}
printf("\nBefore strncpy destination = %s", dest);
strncpy(dest, source, n);
printf("\nAfter strncpy destination = %s\n", dest);
return 0;
}
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